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A compound was found to contain nitrogen and oxygen in the ratio 28 gm and 80 gm respectively. The formula of compound is (1978)
  • a)
    NO
  • b)
    N2O3
  • c)
    N2O5
  • d)
    N2O4
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A compound was found to contain nitrogen and oxygen in the ratio 28 gm...
No. of nitrogen atoms =
No. of oxygen atoms =
∴ Formula of compound is N2O5.
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Most Upvoted Answer
A compound was found to contain nitrogen and oxygen in the ratio 28 gm...
Given:
- Nitrogen content in the compound = 28 gm
- Oxygen content in the compound = 80 gm

To find:
- The formula of the compound

Solution:
The ratio of nitrogen to oxygen can be used to determine the formula of the compound.

1. Finding the number of moles:
- The molar mass of nitrogen (N) = 14 g/mol
- The molar mass of oxygen (O) = 16 g/mol
- Number of moles of nitrogen = Nitrogen content / Molar mass of nitrogen = 28 gm / 14 g/mol = 2 mol
- Number of moles of oxygen = Oxygen content / Molar mass of oxygen = 80 gm / 16 g/mol = 5 mol

2. Simplifying the ratio:
- The ratio of nitrogen to oxygen is 2:5
- To simplify the ratio, divide both numbers by their greatest common divisor (GCD), which is 1 in this case.
- The simplified ratio is 2:5

3. Determining the formula:
- The ratio of 2:5 indicates that there are 2 moles of nitrogen for every 5 moles of oxygen in the compound.
- The formula of the compound can be written as N2O5, where the subscript represents the number of atoms.

Therefore, the correct answer is option C) N2O5.
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A compound was found to contain nitrogen and oxygen in the ratio 28 gm and 80 gm respectively. The formula of compound is (1978)a)NOb)N2O3c)N2O5d)N2O4Correct answer is option 'C'. Can you explain this answer?
Question Description
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