**Given information:**
- Resistance of two conductors in parallel: 12 ohm
- Resistance of two conductors in series: 50 ohm

**To find:**
- Resistance of each conductor

**Solution:**

Let's assume the resistance of the first conductor as R1 and the resistance of the second conductor as R2.

**1. Resistance of the conductors in parallel:**

When two resistors are connected in parallel, the total resistance is given by the formula:

1/Rp = 1/R1 + 1/R2

Given that the resistance of the conductors in parallel is 12 ohm, we can substitute the values:

1/12 = 1/R1 + 1/R2

**2. Resistance of the conductors in series:**

When two resistors are connected in series, the total resistance is the sum of individual resistances:

Rs = R1 + R2

Given that the resistance of the conductors in series is 50 ohm, we can substitute the values:

50 = R1 + R2

**3. Solving the equations:**

We now have two equations:

1/12 = 1/R1 + 1/R2 ...(1)
50 = R1 + R2 ...(2)

We can solve these equations simultaneously to find the values of R1 and R2.

Multiplying equation (1) by 12R1R2, we get:

R2 + R1 = 12R2
R1 = 11R2

Substituting this value in equation (2), we get:

50 = 11R2 + R2
50 = 12R2

Dividing both sides by 12, we get:

R2 = 50/12
R2 = 4.167 ohm

Substituting the value of R2 in equation (2), we get:

R1 = 11 * 4.167
R1 = 45.83 ohm

**Answer:**
The resistance of the first conductor (R1) is approximately 45.83 ohm, and the resistance of the second conductor (R2) is approximately 4.167 ohm.