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In forming a committee of 5 out of 5 males and 6 females how many choices you have to made so that there are 3 males and 2 females?
  • a)
    461
  • b)
    200
  • c)
    1
  • d)
    150
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
In forming a committee of 5 out of 5 males and 6 females how many choi...
5C3 x 6C2 = 5 x 4/2 x 6 x 5/2
=150
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In forming a committee of 5 out of 5 males and 6 females how many choi...
Solution:
To form a committee of 5 members, we need to choose 3 males and 2 females.

Step 1: Choosing 3 males out of 5
We can choose 3 males out of 5 in ^5C3 ways.
^5C3 = (5!)/(3! x 2!) = 10

Step 2: Choosing 2 females out of 6
We can choose 2 females out of 6 in ^6C2 ways.
^6C2 = (6!)/(2! x 4!) = 15

Step 3: Total number of ways of forming a committee of 5 members with 3 males and 2 females
Using the multiplication principle, the total number of ways of forming a committee of 5 members with 3 males and 2 females is given by:
^5C3 x ^6C2 = 10 x 15 = 150

Therefore, the correct answer is option D, 150.
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In forming a committee of 5 out of 5 males and 6 females how many choi...
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In forming a committee of 5 out of 5 males and 6 females how many choices you have to made so that there are 3 males and 2 females?a)461b)200c)1d)150Correct answer is option 'D'. Can you explain this answer?
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