A 280 meter long train moving with an average speed of 108 km/h crosse...
Speed of train = 108km/hr=108*5/18 m/sec = 30m/s
If the length of the platform be x meters,
then
x+280/12=30 x+280=360
x=(360-280)=80m
∴speed of man=80/10 = 8m/s
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A 280 meter long train moving with an average speed of 108 km/h crosse...
To solve this problem, we can use the concept of relative speed. The train is moving with a certain speed, and the man is moving with his own speed. The relative speed between the train and the man can be calculated by subtracting their individual speeds.
Given:
Length of the train (L) = 280 meters
Speed of the train (S1) = 108 km/h
Time taken by the train to cross the platform (T1) = 12 seconds
Time taken by the man to cross the platform (T2) = 10 seconds
Let's calculate the speed of the man (S2):
1. Convert the speed of the train from km/h to m/s:
Speed of the train (S1) = 108 km/h = (108 * 1000) m/3600 s = 30 m/s
2. Calculate the time taken by the train to cross the platform (T1) in m/s:
Time taken by the train to cross the platform (T1) = 12 seconds
Distance covered by the train (D1) = Length of the train (L) = 280 meters
Speed of the train (S1) = Distance covered by the train (D1) / Time taken by the train (T1)
30 = 280 / T1
T1 = 280 / 30 = 9.33 seconds
3. Calculate the speed of the man (S2):
Relative speed = Speed of the train (S1) - Speed of the man (S2)
Relative speed = 30 - S2
The man takes 10 seconds to cross the platform, so the distance covered by the man (D2) is equal to the length of the platform (L).
Relative speed = Distance covered by the man (D2) / Time taken by the man (T2)
30 - S2 = L / T2
30 - S2 = 280 / 10
30 - S2 = 28
S2 = 30 - 28 = 2 m/s
Therefore, the speed of the man is 2 m/s.
Since none of the options given match the calculated speed of the man, it can be concluded that the speed of the man cannot be determined accurately.