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Three 2V cells are connected in series and used as a battery in a circuit a) What is the potential difference at the terminal if the battery b) How many jules of electric energy does 1C gain on passing through (i) one cell (ii) all three cell?
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Three 2V cells are connected in series and used as a battery in a circ...
  1. If three cells of 2 volt each are connected in series to make a battery, then the total potential difference between terminals of the battery will be 6V.
  2. (i) Given: p.d. = 2V, Charge moved = 1C
              We know that, 
p.d. = work done/charge moved
Work done = p.d. x charge moved = 2 x 1
Work done = 2 joules
   (ii) Given: p.d. = 6V, Charge moved = 1C
Work done = p.d. x charge moved
       = 6 x 1
Work done = 6 joule ( 1ST CLICK ON REPLY THEN VEIW ANS TO GET IT CORRECTLY)
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Three 2V cells are connected in series and used as a battery in a circ...
Potential Difference of a Battery

The potential difference of a battery is the difference in electric potential between its positive and negative terminals. In other words, it is the voltage that the battery can provide to a circuit.

Calculation of Potential Difference

When three 2V cells are connected in series, their voltages add up to give a total voltage of:
V = 2V + 2V + 2V = 6V

Therefore, the potential difference at the terminal of the battery is 6V.

Electric Energy Gained by 1 Coulomb

The electric energy gained by 1 coulomb of charge on passing through an electric circuit is given by the formula:
E = VQ

where E is the electric energy gained (in joules), V is the potential difference (in volts), and Q is the charge (in coulombs) that passes through the circuit.

Electric Energy Gained by 1 Coulomb in One Cell

In one cell, the potential difference is 2V. Therefore, the electric energy gained by 1 coulomb of charge on passing through one cell is:
E = VQ = 2V x 1C = 2J

Electric Energy Gained by 1 Coulomb in Three Cells

When three cells are connected in series, the potential difference becomes 6V. Therefore, the electric energy gained by 1 coulomb of charge on passing through all three cells is:
E = VQ = 6V x 1C = 6J

Explanation

When a charge passes through an electric circuit, it gains electric energy equal to the product of the potential difference and the charge. In one cell, the potential difference is 2V, so a charge of 1 coulomb gains 2 joules of energy. When three cells are connected in series, the potential difference becomes 6V, so a charge of 1 coulomb gains 6 joules of energy.
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