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Blocks are in contact on a friction less table a horizontal surface force f=3N is applied to one block as shown. The force exerted by the smaller block m2 on block m1 is- M1=2kg, m2=1kg?
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Blocks are in contact on a friction less table a horizontal surface fo...
Problem: Blocks are in contact on a frictionless table. A horizontal surface force F=3N is applied to one block. The force exerted by the smaller block m2 on block m1 is- M1=2kg, m2=1kg?

Solution:

Step 1: Free Body Diagram
- Draw a free body diagram of the system to visualize the forces acting on the blocks.
- Label the forces acting on the blocks.

Step 2: Analysis of Forces
- The force F=3N is applied to block m1.
- The force of friction between the blocks is zero as the table is frictionless.
- The weight of the blocks is neglected as the table is horizontal.
- The force exerted by m2 on m1 is the reaction force to the force applied by m1 on m2.
- The acceleration of the system is the same for both the blocks.

Step 3: Equations of Motion
- Apply Newton's second law of motion to both the blocks.
- Write the equations of motion in terms of the forces acting on the blocks.
- Use the fact that the acceleration of both the blocks is the same.

Step 4: Solution
- Solve the equations of motion simultaneously to find the force exerted by m2 on m1.
- Substitute the given values of m1 and m2 in the equations.
- The force exerted by m2 on m1 is 1N.

Therefore, the force exerted by the smaller block m2 on block m1 is 1N.
Community Answer
Blocks are in contact on a friction less table a horizontal surface fo...
First find out the net acceleration
a net = Fnet/ m = 3/3 = 1 m/s2
Now F2= m1×a = 1x1= 1N
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Blocks are in contact on a friction less table a horizontal surface force f=3N is applied to one block as shown. The force exerted by the smaller block m2 on block m1 is- M1=2kg, m2=1kg?
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