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A inductive coil connected to a 200V,50Hz supply takes a current 10A.If the power dissipated in the coil is 100W. Calculate the inductance power factor phase angle?
Most Upvoted Answer
A inductive coil connected to a 200V,50Hz supply takes a current 10A.I...
Given:
Voltage (V) = 200V
Frequency (f) = 50Hz
Current (I) = 10A
Power (P) = 100W

Calculating Inductance (L):
The formula to calculate the inductance (L) is:
P = I^2 × R
where R = Resistance of the coil

Since the coil is inductive, the resistance (R) is replaced by the impedance (Z):
Z = √(R^2 + Xl^2)
where Xl = Inductive reactance

The formula for inductive reactance (Xl) is:
Xl = 2πfL

Substituting the above equations in the formula for impedance,
Z = √(R^2 + (2πfL)^2)

Since the coil is connected to an AC supply, the power factor (pf) is given by:
pf = cos(θ)
where θ = Phase angle between voltage and current

Calculating Power factor and Phase angle:
The formula to calculate the power factor (pf) and phase angle (θ) is:
pf = P/(V×I) × 100
θ = cos^-1(pf)

Substituting the given values, we get:
pf = 100/(200×10) × 100 = 0.5 or 50%
θ = cos^-1(0.5) = 60°

Therefore, the inductance of the coil is calculated using the formula:
Z = √(R^2 + (2πfL)^2)
100 = 10^2 × R
R = 10Ω
Z = √(10^2 + (2π×50×L)^2)
Z = √(100 + 157079.63L^2)
Z^2 = 100 + 157079.63L^2
10000 = 100 + 157079.63L^2
L^2 = (10000 - 100)/157079.63
L = 0.318H

Hence, the inductance of the coil is 0.318H, the power factor is 0.5 or 50%, and the phase angle is 60°.
Community Answer
A inductive coil connected to a 200V,50Hz supply takes a current 10A.I...
Inductive coil connected to a 200v , 50hz takes 10a
100w

200 and 100 about to= 2 hz
50hz and 10a = 5 hz

2into 5 = 10 ans
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A inductive coil connected to a 200V,50Hz supply takes a current 10A.If the power dissipated in the coil is 100W. Calculate the inductance power factor phase angle?
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