Introduction:
In a full wave rectifier circuit, a capacitor filter is used to reduce the ripple voltage. The value of capacitance required for the capacitor filter depends on the ripple factor and the load resistance. In this scenario, we are given a full wave rectifier operating at a standard aircraft power frequency of 400Hz and a load resistance of 500ohm. We need to calculate the value of capacitance required to achieve a ripple factor of 10%.

Calculating Ripple Factor:
The ripple factor is given by the formula:

Ripple Factor = Vrms / Vdc

Where Vrms is the root mean square value of the ripple voltage and Vdc is the DC output voltage. The ripple voltage can be calculated using the formula:

Vr = (1 / (2 * f * C)) * Vdc

Where f is the frequency of the input AC signal and C is the capacitance.

Rearranging the formula for the ripple voltage, we get:

C = (1 / (2 * f * Vr)) * Vdc

Calculating the Value of Capacitance:
Given that the ripple factor is 10%, we can substitute the values into the formula to calculate the required capacitance.

Ripple Factor = 0.1
Frequency (f) = 400Hz
Load Resistance (R) = 500ohm

To calculate the capacitance, we need to know the DC output voltage (Vdc). As it is not provided in the question, we will assume a standard value of 10V for demonstration purposes.

Substituting the values into the formula:

C = (1 / (2 * 400 * 0.1)) * 10

C = 0.0125 Farads

Therefore, the value of capacitance required in the capacitor filter is 0.0125 Farads.

Conclusion:
In this scenario, we calculated the value of capacitance required for a capacitor filter connected to a full wave rectifier operating at a standard aircraft power frequency of 400Hz. The calculation was based on achieving a ripple factor of 10% for a load resistance of 500ohm. The calculated value of capacitance was 0.0125 Farads.