**Calculation of Power Factor:**

The power factor (PF) is the ratio of the actual power (P) to the apparent power (S). It indicates the phase relationship between the voltage and current in an AC circuit.

Given:
Supply voltage (V) = 230V
Frequency (f) = 50Hz
Current (I) = 5A
Power dissipated (P) = 750W

The apparent power (S) can be calculated using the formula:
S = V * I

Substituting the given values:
S = 230V * 5A = 1150VA

The power factor (PF) can be calculated as:
PF = P / S

Substituting the given values:
PF = 750W / 1150VA ≈ 0.652

Therefore, the power factor of the coil is approximately 0.652.

**Calculation of Resistance:**

The resistance of the coil can be calculated using the formula:
R = V / I

Substituting the given values:
R = 230V / 5A = 46Ω

Therefore, the resistance of the coil is 46Ω.

**Calculation of Inductance:**

To calculate the inductance of the coil, we need to use the formula:
XL = 2πfL

Where XL is the inductive reactance and L is the inductance.

The inductive reactance (XL) can be calculated using the formula:
XL = V / I

Substituting the given values:
XL = 230V / 5A = 46Ω

The inductive reactance (XL) is equal to the resistance (R) because the coil is purely inductive.

Now, we can calculate the inductance (L) using the formula:
L = XL / (2πf)

Substituting the given values:
L = 46Ω / (2π * 50Hz) ≈ 0.146H

Therefore, the inductance of the coil is approximately 0.146H.

In summary, the power factor of the coil is 0.652, the resistance is 46Ω, and the inductance is 0.146H.