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Two registors R1, and R2 give combined resistance of 4.5 Ω when in series and 1 Ω when in parallel. The resistances are
  • a)
    1 Ω and 3.5 Ω
  • b)
    4 Ω and 0.5 Ω
  • c)
    2 Ω and 2.5 Ω
  • d)
    1.5 Ω and 3 Ω
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Two registors R1, and R2 give combined resistance of 4.5 Ω when ...
R1 + R2 = 4.5 ...(i)
and 
∴ (R1-R2)2 = (R1 + R2)- 4R1R2

or,  ...(ii)
On solving equations (i) and (ii), we get
R1 = 3 Ω and R2 = 1.5 Ω
or, R1 = 1.5 Ω and R2 = 3Ω.
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Most Upvoted Answer
Two registors R1, and R2 give combined resistance of 4.5 Ω when ...
To find the combined resistance of two resistors in series, you simply add their individual resistances together. Therefore, the combined resistance of R1 and R2 is 4.5 ohms.
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Two registors R1, and R2 give combined resistance of 4.5 Ω when in series and 1 Ω when in parallel. The resistances area)1 Ω and 3.5 Ωb)4 Ω and 0.5 Ωc)2 Ω and 2.5 Ωd)1.5 Ω and 3 ΩCorrect answer is option 'D'. Can you explain this answer?
Question Description
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