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The lines 3x+4y+10=0 and 4x-3y+5=0 are ________
  • a)
    Parallel
  • b)
    Perpendicular to each other
  • c)
    Bisect each other
  • d)
    Concide with each other.
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The lines 3x+4y+10=0 and 4x-3y+5=0 are ________a)Parallelb)Perpendicul...
Explanation:

The given two lines are:

3x + 4y + 10 = 0

4x - 3y + 5 = 0

To check whether the given lines are parallel or perpendicular or bisect each other or coincide with each other, we need to find the slope of both the lines.

Slope of the first line:

3x + 4y + 10 = 0

4y = -3x - 10

y = (-3/4)x - 5/2

Slope of the first line is -3/4.

Slope of the second line:

4x - 3y + 5 = 0

-3y = -4x - 5

y = (4/3)x + 5/3

Slope of the second line is 4/3.

Since the product of the slopes of the two lines is -1, the given two lines are perpendicular to each other.

Therefore, the correct answer is option 'B': Perpendicular to each other.
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The lines 3x+4y+10=0 and 4x-3y+5=0 are ________a)Parallelb)Perpendicul...
Perpendicular to each other
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The lines 3x+4y+10=0 and 4x-3y+5=0 are ________a)Parallelb)Perpendicular to each otherc)Bisect each otherd)Concide with each other.Correct answer is option 'B'. Can you explain this answer?
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