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It is given that ar(ΔABC) = 81 square units and ar(ΔDEF) = 64 square units. If ΔABC ~ ΔDEF, then
  • a)
    AB/DE = 81/64
  • b)
  • c)
    AB/DE = 9/8
  • d)
    AB = 81 units, DE = 64 units
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
It is given that ar(ΔABC) = 81 square units and ar(ΔDEF) =...
In triangle ACB and ADC
∠A=∠A
∠ACB = ∠CDA
Therefore triangle ACB and ADC are similar,
Hence
AC/AD = AB/AC
AC2 = AD X AB
82 = 3 x AB
⇒ AB = 64/3
This implies,
BD = 64/3 – AD
⇒ BD = 55/3
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It is given that ar(ΔABC) = 81 square units and ar(ΔDEF) =...
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Community Answer
It is given that ar(ΔABC) = 81 square units and ar(ΔDEF) =...
Option c ,abc/def=9/8
9^2=81
8^2=64
if it all get divided the answer will be 9/8
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It is given that ar(ΔABC) = 81 square units and ar(ΔDEF) = 64 square units. If ΔABC ~ ΔDEF, thena)AB/DE = 81/64b)c)AB/DE = 9/8d)AB = 81 units, DE = 64 unitsCorrect answer is option 'C'. Can you explain this answer?
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