Area of a quadrant of circle whose circumference is 22 cm is : (= 22/7...
• Circumference of a circle = 2πr
• Area of quadrant = 1/4πr^2
Solution :-
• Circumference of a circle = 2πr
22 cm = 2 × 22/7 × r
r = 22 cm × 7/44
r = 3.5 cm
• Area of quadrant = 1/4πr^2
= 1/4 × 22/7 × ( 3.5 cm )^2
= 1/4 × 22/7 × 12.25 cm^2
= 1/4 × 22 × 1.75cm^2
= 5.5 × 1.75cm^2
= 9.625cm^2
~ Hence , option A is correct answer .
|| hope you understand ||
¶¶ Thnxx ¶¶
Area of a quadrant of circle whose circumference is 22 cm is : (= 22/7...
To find the area of a quadrant of a circle, we need to know the radius of the circle. However, the given information only provides the circumference of the circle.
To find the radius of the circle, we can use the formula for the circumference of a circle:
C = 2πr
where C is the circumference and r is the radius.
In this case, the circumference is given as 22 cm and π is approximately 22/7. So we can rewrite the formula as:
22 = 2(22/7)r
Simplifying the equation, we get:
22 = 44/7r
To isolate the r, we can multiply both sides of the equation by 7/44:
(22)(7/44) = r
Simplifying, we find that the radius is:
r = 3.5 cm
Now that we know the radius, we can find the area of the quadrant using the formula for the area of a quadrant:
Area = (1/4)πr^2
Substituting the values, we have:
Area = (1/4)(22/7)(3.5)^2
Simplifying, we get:
Area = (1/4)(22/7)(12.25)
Area = (22/28)(12.25)
Area = 9.625 cm^2
Hence, the correct answer is option A, 9.625 cm^2.