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How many numbers with two or more digits can be formed with the digits 1,2,3,4,5,6,7,8,9, so that in every such number, each digit is used at most once and the digits appear in the ascending order?
(2018)
  • a)
    500
  • b)
    502
  • c)
    501
  • d)
    504
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
How many numbers with two or more digits can be formed with the digits...
As the digits appear in ascending order in the numbers, number of ways of forming a n-digit number using the 9 digits = 9Cn
Number of possible two-digit numbers which can be formed
= 9C2 + 9C3 + 9C4 + 9C5 + 9C6 + 9C7 + 9C8 + 9C9
= (1 + 1)9 – (9C0 + 9C1) = 29 – (9C0 + 9C1) = 512 – (1 + 9) = 502
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How many numbers with two or more digits can be formed with the digits 1,2,3,4,5,6,7,8,9, so that in every such number, each digit is used at most once and the digits appear in the ascending order?(2018)a)500b)502c)501d)504Correct answer is option 'B'. Can you explain this answer?
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