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A block released from rest from the top of a smooth inclined plane of inclination q, has a speed u when it reaches the bottom. The same block released from the top of a rough inclined plane of the same inclination q, has a speed u/n on reaching the bottom, where n is a number greater than unity. The coefficient of friction is given by?
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Introduction:

When a block is released from rest from the top of a smooth inclined plane, it accelerates due to the force of gravity. However, when the same block is released from the top of a rough inclined plane, the presence of friction opposes the motion, reducing the speed of the block at the bottom.

Explanation:

Smooth Inclined Plane:

When a block is released from rest from the top of a smooth inclined plane, the only force acting on it is the force of gravity. The force of gravity can be resolved into two components: one parallel to the inclined plane and the other perpendicular to the inclined plane.

The component of the force of gravity parallel to the inclined plane causes the block to accelerate down the incline. The acceleration can be calculated using the equation:

a = gsin(q)

Where a is the acceleration, g is the acceleration due to gravity, and q is the angle of inclination.

The block continues to accelerate as it moves down the incline until it reaches the bottom. The final speed of the block at the bottom can be calculated using the equation:

v = usqrt(2gh)

Where v is the final speed, u is the initial speed (which is zero in this case), g is the acceleration due to gravity, and h is the height of the incline.

Rough Inclined Plane:

When a block is released from rest from the top of a rough inclined plane, the force of friction opposes the motion of the block. The force of friction can be calculated using the equation:

f = μN

Where f is the force of friction, μ is the coefficient of friction, and N is the normal force.

The normal force can be calculated using the equation:

N = mgcos(q)

Where m is the mass of the block and g is the acceleration due to gravity.

The force of friction acts opposite to the direction of motion, causing the block to decelerate. The deceleration can be calculated using the equation:

a = f/m

Where a is the deceleration, f is the force of friction, and m is the mass of the block.

The block decelerates as it moves down the incline until it reaches the bottom. The final speed of the block at the bottom can be calculated using the equation:

v = u - at

Where v is the final speed, u is the initial speed (which is zero in this case), a is the deceleration, and t is the time taken to reach the bottom.

Coefficient of Friction:

From the above equations, we can see that the final speed of the block at the bottom of the rough inclined plane is reduced compared to the smooth inclined plane. This reduction in speed is due to the presence of friction, which opposes the motion of the block.

The coefficient of friction can be calculated using the equations:

f = μN

a = f/m

v = u - at

By substituting the values of f, N, and a from the above equations, we can solve for μ:

μ = a/(gcos(q))

Where μ is the coefficient of friction, a is the deceleration, g is the acceleration due to gravity, and q is the angle of inclination.

Therefore, the coefficient of friction is given by μ = a/(gcos(q)), where a is the deceleration and q is
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A block released from rest from the top of a smooth inclined plane of inclination q, has a speed u when it reaches the bottom. The same block released from the top of a rough inclined plane of the same inclination q, has a speed u/n on reaching the bottom, where n is a number greater than unity. The coefficient of friction is given by?
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