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In a discrete random variable x follows uniform distribution and assumes only the values 8, 9, 11, 15, 18, 20. Then P(x > 15) is
- a)2/3
- b)1/3
- c)1
- d)none
Correct answer is option 'B'. Can you explain this answer?
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In a discrete random variable x follows uniform distribution and assum...
Uniform Distribution
The uniform distribution is a discrete probability distribution where all outcomes are equally likely. In other words, each value in the distribution has the same probability of occurring.
Given Information
In this question, we are given that the random variable x follows a uniform distribution and assumes the values 8, 9, 11, 15, 18, and 20. We need to find the probability that x is greater than 15, i.e., P(x > 15).
Calculating the Probability
To calculate the probability, we need to find the number of favorable outcomes and divide it by the total number of outcomes.
Favorable Outcomes
In this case, the favorable outcomes are the values of x that are greater than 15. From the given information, we can see that the values 18 and 20 are greater than 15. So, there are 2 favorable outcomes.
Total Outcomes
The total number of outcomes is the number of values that x can assume, which is 6 in this case.
Calculating the Probability
To calculate the probability, we divide the number of favorable outcomes by the total number of outcomes:
P(x > 15) = Number of favorable outcomes / Total number of outcomes
P(x > 15) = 2 / 6
P(x > 15) = 1/3
Therefore, the probability that x is greater than 15, i.e., P(x > 15), is 1/3.
Conclusion
In this question, we used the concept of a uniform distribution to calculate the probability that a random variable x is greater than 15. We found that the probability is 1/3.
The uniform distribution is a discrete probability distribution where all outcomes are equally likely. In other words, each value in the distribution has the same probability of occurring.
Given Information
In this question, we are given that the random variable x follows a uniform distribution and assumes the values 8, 9, 11, 15, 18, and 20. We need to find the probability that x is greater than 15, i.e., P(x > 15).
Calculating the Probability
To calculate the probability, we need to find the number of favorable outcomes and divide it by the total number of outcomes.
Favorable Outcomes
In this case, the favorable outcomes are the values of x that are greater than 15. From the given information, we can see that the values 18 and 20 are greater than 15. So, there are 2 favorable outcomes.
Total Outcomes
The total number of outcomes is the number of values that x can assume, which is 6 in this case.
Calculating the Probability
To calculate the probability, we divide the number of favorable outcomes by the total number of outcomes:
P(x > 15) = Number of favorable outcomes / Total number of outcomes
P(x > 15) = 2 / 6
P(x > 15) = 1/3
Therefore, the probability that x is greater than 15, i.e., P(x > 15), is 1/3.
Conclusion
In this question, we used the concept of a uniform distribution to calculate the probability that a random variable x is greater than 15. We found that the probability is 1/3.
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In a discrete random variable x follows uniform distribution and assumes only the values 8, 9, 11, 15, 18, 20. Then P(x 15) isa)2/3b)1/3c)1d)noneCorrect answer is option 'B'. Can you explain this answer?
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