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The velocity of a particle at an instant is 10m/s . After 5second , the velocity of a particle is 20m/s . The velocity at 3second before is?
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Given:
Initial velocity (u) = 10 m/s
Final velocity (v) = 20 m/s
Time interval (t) = 5 seconds

Using the formula for average velocity:
Average velocity (v_avg) = (v - u) / t

Substituting the given values:
v_avg = (20 - 10) / 5
= 10 / 5
= 2 m/s

Understanding average velocity:
Average velocity is the total displacement divided by the total time taken. It represents the overall change in position of the particle during the given time interval.

Determining displacement:
Displacement (s) = v_avg * t

Substituting the known values:
s = 2 * 5
= 10 m

Determining the velocity 3 seconds before:
To find the velocity 3 seconds before the given time interval, we need to subtract 3 seconds from the given time interval.

Calculating the time:
New time interval = t - 3
= 5 - 3
= 2 seconds

Determining the velocity:
Using the formula for average velocity again, we can find the velocity at 3 seconds before:

v_avg = (20 - u) / (t - 3)

Substituting the known values:
2 = (20 - u) / 2

Isolating 'u' (initial velocity):
20 - u = 4
u = 20 - 4
u = 16 m/s

Conclusion:
Therefore, the velocity of the particle 3 seconds before is 16 m/s.
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The velocity of a particle at an instant is 10m/s . After 5second , the velocity of a particle is 20m/s . The velocity at 3second before is?
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