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A mass m of a liquid at temperature T1 is mixed with an equal mass of same liquid at temperature T2. The system is thermally insulated. show that the entropy change of the universe is. *?
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A mass m of a liquid at temperature T1 is mixed with an equal mass of ...
Entropy Change of the Universe in Mixing Equal Masses of Liquid

Initial State:
- Mass of liquid at temperature T1 = m
- Mass of liquid at temperature T2 = m
- Total mass = 2m
- System is thermally insulated

Entropy Change:
- Entropy change of the universe can be calculated using the formula: ΔS = ΔS1 + ΔS2
- ΔS1 = m * c * ln(Tf/T1) where c is the specific heat capacity of the liquid and Tf is the final temperature after mixing
- ΔS2 = m * c * ln(Tf/T2)
- Since the system is thermally insulated, there is no heat exchange with the surroundings, and the total entropy change is 0

Final State:
- The final temperature Tf can be calculated using the principle of energy conservation: m * c * (Tf - T1) + m * c * (Tf - T2) = 0
- Solving the equation, we get Tf = (T1 + T2) / 2

Conclusion:
- The entropy change of the universe when equal masses of liquid at different temperatures are mixed in a thermally insulated system is 0, as there is no net change in entropy due to the absence of heat exchange with the surroundings.
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A mass m of a liquid at temperature T1 is mixed with an equal mass of same liquid at temperature T2. The system is thermally insulated. show that the entropy change of the universe is. *?
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