A student placed a Zn rod in the FeSO4 solution. After 10 hours when t...
A student placed a Zn rod in the FeSO4 solution. After 10 hours when t...
Explanation:
When a Zn rod is placed in an FeSO4 solution, a redox reaction occurs due to the difference in the standard electrode potentials of Zn and Fe. The Zn rod acts as an anode, and the FeSO4 solution acts as a cathode. The following reaction occurs:
Zn(s) → Zn2+(aq) + 2e- (oxidation)
Fe2+(aq) + 2e- → Fe(s) (reduction)
As a result of this reaction, the Zn rod undergoes corrosion and becomes thinner. However, the Fe ions that are reduced at the cathode can also deposit on the Zn rod, resulting in an increase in thickness. This deposition of Fe is known as electroplating.
So, why is the correct answer option D?
Option D states that the Zn rod has holes after 10 hours in the FeSO4 solution. This is because the Zn rod undergoes localized corrosion due to the formation of an electrochemical cell. The areas where the Zn is in contact with the FeSO4 solution become anodic, while the areas where the Fe ions deposit become cathodic. As a result, the Zn undergoes pitting corrosion, and holes form on the surface of the rod.
In summary, when a Zn rod is placed in an FeSO4 solution, it undergoes corrosion due to the redox reaction that occurs. It can also undergo electroplating if Fe ions deposit on its surface. However, if the corrosion is localized, pitting corrosion can occur, leading to the formation of holes on the surface of the rod.