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The wages of 8 men and 6 boys amount of Rs. 33. If 4 men earn Rs. 4.50 more then 5 boys determine the wages of each man and boy.
- a)(Rs. 1.50, Rs. 3)
- b)(Rs. 3, Rs.1.50)
- c)(Rs. 2.50, Rs. 2)
- d)(Rs. 2, Rs. 2.50)
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The wages of 8 men and 6 boys amount of Rs. 33. If 4 men earn Rs. 4.50...
Given:
- Wages of 8 men and 6 boys = Rs. 33
- 4 men earn Rs. 4.50 more than 5 boys
To find:
- Wages of each man and boy
Solution:
Let's assume the wages of each man = x
and the wages of each boy = y
According to the given conditions, we can form the following equations:
1. 8x + 6y = 33 ... (i) [The wages of 8 men and 6 boys amount of Rs. 33]
2. 4x = 5y + 4.50 ... (ii) [4 men earn Rs. 4.50 more than 5 boys]
We can solve these two equations to get the values of x and y.
From equation (ii), we can find the value of y in terms of x:
5y = 4x - 4.50
y = (4/5)x - 0.90
Substituting this value of y in equation (i), we get:
8x + 6((4/5)x - 0.90) = 33
Simplifying this equation:
8x + (24/5)x - 5.40 = 33
Multiplying both sides by 5 to remove the fraction:
40x + 24x - 27 = 165
64x = 192
x = 3
Substituting the value of x in equation (ii), we get:
4(3) = 5y + 4.50
12 - 4.50 = 5y
7.50 = 5y
y = 1.50
Therefore, the wages of each man = Rs. 3 and the wages of each boy = Rs. 1.50.
Hence, the correct answer is option (B).
- Wages of 8 men and 6 boys = Rs. 33
- 4 men earn Rs. 4.50 more than 5 boys
To find:
- Wages of each man and boy
Solution:
Let's assume the wages of each man = x
and the wages of each boy = y
According to the given conditions, we can form the following equations:
1. 8x + 6y = 33 ... (i) [The wages of 8 men and 6 boys amount of Rs. 33]
2. 4x = 5y + 4.50 ... (ii) [4 men earn Rs. 4.50 more than 5 boys]
We can solve these two equations to get the values of x and y.
From equation (ii), we can find the value of y in terms of x:
5y = 4x - 4.50
y = (4/5)x - 0.90
Substituting this value of y in equation (i), we get:
8x + 6((4/5)x - 0.90) = 33
Simplifying this equation:
8x + (24/5)x - 5.40 = 33
Multiplying both sides by 5 to remove the fraction:
40x + 24x - 27 = 165
64x = 192
x = 3
Substituting the value of x in equation (ii), we get:
4(3) = 5y + 4.50
12 - 4.50 = 5y
7.50 = 5y
y = 1.50
Therefore, the wages of each man = Rs. 3 and the wages of each boy = Rs. 1.50.
Hence, the correct answer is option (B).
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The wages of 8 men and 6 boys amount of Rs. 33. If 4 men earn Rs. 4.50 more then 5 boys determine the wages of each man and boy.a)(Rs. 1.50, Rs. 3)b)(Rs. 3, Rs.1.50)c)(Rs. 2.50, Rs. 2)d)(Rs. 2, Rs. 2.50)Correct answer is option 'B'. Can you explain this answer?
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