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The wages of 8 men and 6 boys amount to Rs. 33. If 4 men earn Rs. 4.50 more than 5 boys determine the wages of each man and boy.
- a)(Rs. 1.50, Rs. 3)
- b)(Rs. 3, Rs. 1.50)
- c)(Rs. 2.50, Rs. 2)
- d)(Rs. 2, Rs. 2.50)
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The wages of 8 men and 6 boys amount to Rs. 33. If 4 men earn Rs. 4.50...
Let the wage of 1 man be rs x and the wage of 1 boy be rs y.
Now, 8x+6y=33
and, 4x=4.5+5y
also, 8x=2(4x)=2(4.5+5y)=9+10y
So,8x=9+10y
Thus, 9+10y+6y=33
9+16y=33
16y=33–9
16y=24
y=24/16
y=1.5
Now, 8x+6(1.5)=33
8x+9=33
8x=33–9
8x=24
x=24/8
x=3
So, the wage of each man is rs 3 while the wage of each boy is rs 1.5.
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Community Answer
The wages of 8 men and 6 boys amount to Rs. 33. If 4 men earn Rs. 4.50...
Given information:
- The wages of 8 men and 6 boys amount to Rs. 33.
- 4 men earn Rs. 4.50 more than 5 boys.
To find:
- Wages of each man and boy.
Solution:
Let the wages of one man be Rs. m and the wages of one boy be Rs. b.
From the first statement, we can form the equation:
8m + 6b = 33 ...(1)
From the second statement, we know that:
4m = 5b + 4.50
Rearranging this equation, we get:
4m - 5b = 4.50 ...(2)
Now, we have two equations with two variables. We can solve for m and b by eliminating one variable.
Multiplying equation (2) by 2, we get:
8m - 10b = 9 ...(3)
Adding equations (1) and (3), we get:
8m + 6b + 8m - 10b = 33 + 9
16m - 4b = 42
Dividing both sides by 4, we get:
4m - b = 10.5 ...(4)
Now, we have two equations with two variables again. We can solve for m and b by substitution.
Substituting equation (4) into equation (1), we get:
8m + 6(4m-10.5) = 33
Simplifying this equation, we get:
44m = 87
m = 1.98
Substituting m = 1.98 into equation (4), we get:
4(1.98) - b = 10.5
b = 1.47
Therefore, the wages of each man is Rs. 1.98 and the wages of each boy is Rs. 1.47.
Answer: Option (B)
- The wages of 8 men and 6 boys amount to Rs. 33.
- 4 men earn Rs. 4.50 more than 5 boys.
To find:
- Wages of each man and boy.
Solution:
Let the wages of one man be Rs. m and the wages of one boy be Rs. b.
From the first statement, we can form the equation:
8m + 6b = 33 ...(1)
From the second statement, we know that:
4m = 5b + 4.50
Rearranging this equation, we get:
4m - 5b = 4.50 ...(2)
Now, we have two equations with two variables. We can solve for m and b by eliminating one variable.
Multiplying equation (2) by 2, we get:
8m - 10b = 9 ...(3)
Adding equations (1) and (3), we get:
8m + 6b + 8m - 10b = 33 + 9
16m - 4b = 42
Dividing both sides by 4, we get:
4m - b = 10.5 ...(4)
Now, we have two equations with two variables again. We can solve for m and b by substitution.
Substituting equation (4) into equation (1), we get:
8m + 6(4m-10.5) = 33
Simplifying this equation, we get:
44m = 87
m = 1.98
Substituting m = 1.98 into equation (4), we get:
4(1.98) - b = 10.5
b = 1.47
Therefore, the wages of each man is Rs. 1.98 and the wages of each boy is Rs. 1.47.
Answer: Option (B)
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The wages of 8 men and 6 boys amount to Rs. 33. If 4 men earn Rs. 4.50 more than 5 boys determine the wages of each man and boy.a)(Rs. 1.50, Rs. 3)b)(Rs. 3, Rs. 1.50)c)(Rs. 2.50, Rs. 2)d)(Rs. 2, Rs. 2.50)Correct answer is option 'B'. Can you explain this answer?
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