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Two equal vessels A and B contain 60% of sugar and 40% of sugar respectively and the remaining Rava. In which 40 litres of mixture is taken out from vessel A and replaced into vessel B. Find the initial quantity of vessel if the final ratio of sugar and Rava in vessel B is 16 : 19 ?

  • a)
    80 litres

  • b)
    100 litres

  • c)
    120 litres

  • d)
    90 litres

Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Two equal vessels A and B contain 60% of sugar and 40% of sugar respec...
Vessel A Sugar and Rava ratio = 3 : 2 Vessel B sugar and Rava ratio = 2 : 3


Given,


In vessel A    (3/5 x 40 = 24)       (2/5 x 40 = 16)


(2x + 24)/(3x + 16) = 16/19


38x + 456 = 48x + 256


10x= 200


x = 20 litres


Initial quantity = x*5 = 100 litres


 


 
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Two equal vessels A and B contain 60% of sugar and 40% of sugar respec...
Problem Statement:

Two equal vessels A and B contain 60% of sugar and 40% of sugar respectively and the remaining Rava. In which 40 litres of mixture is taken out from vessel A and replaced into vessel B. Find the initial quantity of vessel if the final ratio of sugar and Rava in vessel B is 16 : 19?

Solution:

Let the initial quantity of each vessel be x litres.

Quantity of sugar in vessel A = 60% of x = 0.6x

Quantity of sugar in vessel B = 40% of x = 0.4x

Let 40 litres of the mixture be taken out from vessel A.

After taking out 40 litres of mixture from vessel A, the quantity of sugar in vessel A = 0.6x - (0.6x × 40/100) = 0.36x

After adding the same 40 litres of mixture into vessel B, the quantity of sugar in vessel B = 0.4x + (0.6x × 40/100) = 0.64x

Let the final quantity of mixture in vessel B be y litres.

Given that the final ratio of sugar and Rava in vessel B is 16 : 19.

Therefore, the quantity of sugar in vessel B = (16/35) y

And the quantity of Rava in vessel B = (19/35) y

Equating the quantity of sugar in vessel B, we get:

0.64x = (16/35) y

Simplifying the above equation, we get:

y = (35 × 0.64x)/16 = 1.4x

Equating the quantity of Rava in vessel B, we get:

(19/35) y = (60/100) × x + (40/100) × (y - x)

Simplifying the above equation, we get:

19y = 54x + 40y - 40x

Solving for y, we get:

y = (14/19) x

Substituting the value of y in terms of x, we get:

(14/19) x = 1.4x

Solving for x, we get:

x = 100 litres

Therefore, the initial quantity of each vessel is 100 litres.
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Two equal vessels A and B contain 60% of sugar and 40% of sugar respectively and the remaining Rava. In which 40 litres of mixture is taken out from vessel A and replaced into vessel B. Find the initial quantity of vessel if the final ratio of sugar and Rava in vessel B is 16 : 19 ?a)80 litresb)100 litresc)120 litresd)90 litresCorrect answer is option 'B'. Can you explain this answer?
Question Description
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