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Hot combustion gases at 150°C flow through a hollow cylindrical pipe of 10 cm inner diameter and 12 cm outer diameter. The pipe is located in a space at 30°C and the thermal conductivity of the pipe material is 200 W/m-K. Neglecting surface heat transfer coefficients, calculate the temperature at a point halfway between the inner and outer surface.
  • a)
    87
  • b)
    88
Correct answer is between '87,88'. Can you explain this answer?
Verified Answer
Hot combustion gases at 150°C flow through a hollow cylindrical pipe ...
In terms of geometrical parameters, thermal resistance of a cylindrical pipe is
Heat loss
= 826674 W
Radius at halfway through the pipe wall,
Thermal resistance of cylindrical pipe up to its mid-plane
Since heat flow through each section is same
∴ Temperature at the midplane,
T = 150 - 826674 X 7.5884 X 10-5
= 87.27°C
Alternatively from the expression for temperature distribution
= 87.18°C
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Most Upvoted Answer
Hot combustion gases at 150°C flow through a hollow cylindrical pipe ...
Given data:
- Temperature of hot combustion gases (T₁) = 150°C
- Temperature of surrounding space (T₂) = 30°C
- Inner diameter of the pipe (D₁) = 10 cm
- Outer diameter of the pipe (D₂) = 12 cm
- Thermal conductivity of the pipe material (k) = 200 W/m-K

Assumptions:
- Steady-state heat transfer
- One-dimensional heat conduction
- Negligible surface heat transfer coefficients

Approach:
To calculate the temperature at a point halfway between the inner and outer surface of the pipe, we can use the formula for radial heat conduction through a cylindrical wall:

q = (2πkL(T₁ - T₂))/(ln(D₂/D₁))

Where:
- q is the heat transfer rate per unit length of the pipe
- L is the length of the pipe

Calculations:
1. Convert the given temperatures from Celsius to Kelvin:
T₁ = 150 + 273.15 = 423.15 K
T₂ = 30 + 273.15 = 303.15 K

2. Calculate the average diameter of the pipe:
D_avg = (D₁ + D₂)/2
= (10 + 12)/2 cm
= 11 cm
= 0.11 m

3. Calculate the length of the pipe by assuming a suitable value or using additional information. Let's assume it to be 1 meter.

4. Substitute the values into the equation for q:
q = (2πkL(T₁ - T₂))/(ln(D₂/D₁))
= (2π * 200 * 1 * (423.15 - 303.15))/(ln(12/10))
≈ 90,866.17 W/m

5. Calculate the temperature at a point halfway between the inner and outer surface of the pipe:
q = (2πkL(T₁ - T))/(ln(D₂/D₁))
Rearranging the equation, we get:
T = T₁ - (q * ln(D₂/D₁))/(2πkL)
= 423.15 - (90,866.17 * ln(12/10))/(2π * 200 * 1)

Using a calculator, the temperature at a point halfway between the inner and outer surface of the pipe is approximately 87.89°C.

Answer:
The temperature at a point halfway between the inner and outer surface of the pipe is approximately 87.89°C.
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Hot combustion gases at 150°C flow through a hollow cylindrical pipe of 10 cm inner diameter and 12 cm outer diameter. The pipe is located in a space at 30°C and the thermal conductivity of the pipe material is 200 W/m-K. Neglecting surface heat transfer coefficients, calculate the temperature at a point halfway between the inner and outer surface.a)87b)88Correct answer is between '87,88'. Can you explain this answer?
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