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In a cylindrical fuel rod of a nuclear reactor, heat is generated internally according to the equation where is the local rate of heat generation per unit volume at radius r,r0 is the outside radius, and is the rate of heat generation per unit volume at the centre line. Calculate the temperature drop from the centre line to the surface for a 2.5 cm outer diameter rod having k = 20 W/m-K, if the rate of heat removal from the surface is 1650 kW/m2.
  • a)
    617
  • b)
    619
Correct answer is between '617,619'. Can you explain this answer?
Verified Answer
In a cylindrical fuel rod of a nuclear reactor, heat is generated int...
In cylindrical coordinates, the radial variation of temperature at steady state when there is internal heat generation is given by figure
Heat transferred from the rod
This is the volumetric heat generation at the centre line of the rod. Now,
At , r = 0, T = Tc, the centre line temperature
C2 = Tc
At, r = r0, the temperature drop,
= 618.7°C
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Most Upvoted Answer
In a cylindrical fuel rod of a nuclear reactor, heat is generated int...
In cylindrical coordinates, the radial variation of temperature at steady state when there is internal heat generation is given by figure
Heat transferred from the rod
This is the volumetric heat generation at the centre line of the rod. Now,
At , r = 0, T = Tc, the centre line temperature
C2 = Tc
At, r = r0, the temperature drop,
= 618.7°C
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Community Answer
In a cylindrical fuel rod of a nuclear reactor, heat is generated int...
In cylindrical coordinates, the radial variation of temperature at steady state when there is internal heat generation is given by figure
Heat transferred from the rod
This is the volumetric heat generation at the centre line of the rod. Now,
At , r = 0, T = Tc, the centre line temperature
C2 = Tc
At, r = r0, the temperature drop,
= 618.7°C
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In a cylindrical fuel rod of a nuclear reactor, heat is generated internally according to the equation where is the local rate of heat generation per unit volume at radius r,r0 is the outside radius, and is the rate of heat generation per unit volume at the centre line. Calculate the temperature drop from the centre line to the surface for a 2.5 cm outer diameter rod having k = 20 W/m-K, if the rate of heat removal from the surface is 1650 kW/m2.a)617b)619Correct answer is between '617,619'. Can you explain this answer?
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In a cylindrical fuel rod of a nuclear reactor, heat is generated internally according to the equation where is the local rate of heat generation per unit volume at radius r,r0 is the outside radius, and is the rate of heat generation per unit volume at the centre line. Calculate the temperature drop from the centre line to the surface for a 2.5 cm outer diameter rod having k = 20 W/m-K, if the rate of heat removal from the surface is 1650 kW/m2.a)617b)619Correct answer is between '617,619'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about In a cylindrical fuel rod of a nuclear reactor, heat is generated internally according to the equation where is the local rate of heat generation per unit volume at radius r,r0 is the outside radius, and is the rate of heat generation per unit volume at the centre line. Calculate the temperature drop from the centre line to the surface for a 2.5 cm outer diameter rod having k = 20 W/m-K, if the rate of heat removal from the surface is 1650 kW/m2.a)617b)619Correct answer is between '617,619'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a cylindrical fuel rod of a nuclear reactor, heat is generated internally according to the equation where is the local rate of heat generation per unit volume at radius r,r0 is the outside radius, and is the rate of heat generation per unit volume at the centre line. Calculate the temperature drop from the centre line to the surface for a 2.5 cm outer diameter rod having k = 20 W/m-K, if the rate of heat removal from the surface is 1650 kW/m2.a)617b)619Correct answer is between '617,619'. Can you explain this answer?.
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