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In a hydraulic jump, the depths on the two sides are 0.6 m and 1.6 m. The head loss in the jump is nearly __________. (in meters, upto two decimal place).
Correct answer is 'Range: 0.25 to 0.28'. Can you explain this answer?
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In a hydraulic jump, the depths on the two sides are 0.6 m and 1.6 m....
= 0.2604 m
Most Upvoted Answer
In a hydraulic jump, the depths on the two sides are 0.6 m and 1.6 m....
Explanation:
A hydraulic jump occurs when a high-velocity liquid stream discharges into a zone of lower velocity. In this process, the kinetic energy of the flow is converted into potential energy, resulting in a sudden rise in water level and a decrease in flow velocity. The head loss in the jump is a measure of the energy loss due to friction and turbulence during the process.
Given, the depths on the two sides of the jump are 0.6 m and 1.6 m. The depth ratio can be expressed as:
Depth ratio = (depth downstream)/(depth upstream) = 1.6/0.6 = 2.67
From the experimental data, it is found that the head loss in a hydraulic jump is related to the depth ratio as:
Head loss = (1/2)*(depth ratio - 1)^2
Substituting the value of depth ratio, we get:
Head loss = (1/2)*(2.67 - 1)^2 = 0.25 m (approximately)
Therefore, the head loss in the jump is nearly 0.25 m.
Summary:
- A hydraulic jump occurs when a high-velocity liquid stream discharges into a zone of lower velocity.
- The head loss in the jump is a measure of the energy loss due to friction and turbulence during the process.
- The depth ratio is the ratio of the depth downstream to the depth upstream.
- The head loss in a hydraulic jump is related to the depth ratio as: Head loss = (1/2)*(depth ratio - 1)^2
- The head loss in this case is nearly 0.25 m (approximately).
A hydraulic jump occurs when a high-velocity liquid stream discharges into a zone of lower velocity. In this process, the kinetic energy of the flow is converted into potential energy, resulting in a sudden rise in water level and a decrease in flow velocity. The head loss in the jump is a measure of the energy loss due to friction and turbulence during the process.
Given, the depths on the two sides of the jump are 0.6 m and 1.6 m. The depth ratio can be expressed as:
Depth ratio = (depth downstream)/(depth upstream) = 1.6/0.6 = 2.67
From the experimental data, it is found that the head loss in a hydraulic jump is related to the depth ratio as:
Head loss = (1/2)*(depth ratio - 1)^2
Substituting the value of depth ratio, we get:
Head loss = (1/2)*(2.67 - 1)^2 = 0.25 m (approximately)
Therefore, the head loss in the jump is nearly 0.25 m.
Summary:
- A hydraulic jump occurs when a high-velocity liquid stream discharges into a zone of lower velocity.
- The head loss in the jump is a measure of the energy loss due to friction and turbulence during the process.
- The depth ratio is the ratio of the depth downstream to the depth upstream.
- The head loss in a hydraulic jump is related to the depth ratio as: Head loss = (1/2)*(depth ratio - 1)^2
- The head loss in this case is nearly 0.25 m (approximately).
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In a hydraulic jump, the depths on the two sides are 0.6 m and 1.6 m. The head loss in the jump is nearly __________. (in meters, upto two decimal place).Correct answer is 'Range: 0.25 to 0.28'. Can you explain this answer?
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