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A copper wire of radius 0.5 mm is insulated with a sheathing of thickness 1 mm having a thermal conductivity of 0.5 W/m-K. The outside surface convective heat transfer coefficient is 10 W/m2-K. If the thickness of insulation sheathing is raised by 10 mm, then the electrical current-carrying capacity of the wire will
- a)increase
- b)decrease
- c)remain the same
- d)vary depending upon the electrical conductivity of the wire
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A copper wire of radius 0.5 mm is insulated with a sheathing of thick...
But according to the given data the initial value of outer radius of insulation is rin = 0.5 = 1 = 1.5 mm
If the radius of insulation is less than the critical radius, then by adding insulation, heat transfer rate increases. So by increasing the insulation by 10 mm, the radius of insulation will become 11.5 mm that means the heat transfer rate will also increase. That’s why the current carrying capacity of wire will also increase.
Most Upvoted Answer
A copper wire of radius 0.5 mm is insulated with a sheathing of thick...
Explanation:
To understand how increasing the thickness of insulation sheathing affects the current-carrying capacity of a copper wire, we need to consider the following:
1. Heat dissipation: When an electric current flows through a copper wire, it generates heat due to the resistance of the wire. This heat needs to be dissipated to prevent the wire from overheating and melting. The rate of heat dissipation depends on the thermal conductivity of the wire and the convective heat transfer coefficient of the surrounding medium.
2. Insulation: The insulation sheathing around the wire reduces the rate of heat dissipation by increasing the thermal resistance of the system. A thicker insulation sheathing will have a higher thermal resistance, which means that less heat will be dissipated from the wire.
3. Current-carrying capacity: The current-carrying capacity of a wire is limited by the amount of heat it can dissipate. If the wire generates more heat than it can dissipate, its temperature will rise, and it may become damaged or fail.
Based on the above considerations, we can conclude that increasing the thickness of insulation sheathing will increase the current-carrying capacity of the wire. This is because a thicker insulation sheathing will reduce the rate of heat dissipation from the wire, which means that the wire can carry more current without overheating.
In summary, the correct answer is option 'A' – increasing the thickness of insulation sheathing will increase the current-carrying capacity of the wire.
To understand how increasing the thickness of insulation sheathing affects the current-carrying capacity of a copper wire, we need to consider the following:
1. Heat dissipation: When an electric current flows through a copper wire, it generates heat due to the resistance of the wire. This heat needs to be dissipated to prevent the wire from overheating and melting. The rate of heat dissipation depends on the thermal conductivity of the wire and the convective heat transfer coefficient of the surrounding medium.
2. Insulation: The insulation sheathing around the wire reduces the rate of heat dissipation by increasing the thermal resistance of the system. A thicker insulation sheathing will have a higher thermal resistance, which means that less heat will be dissipated from the wire.
3. Current-carrying capacity: The current-carrying capacity of a wire is limited by the amount of heat it can dissipate. If the wire generates more heat than it can dissipate, its temperature will rise, and it may become damaged or fail.
Based on the above considerations, we can conclude that increasing the thickness of insulation sheathing will increase the current-carrying capacity of the wire. This is because a thicker insulation sheathing will reduce the rate of heat dissipation from the wire, which means that the wire can carry more current without overheating.
In summary, the correct answer is option 'A' – increasing the thickness of insulation sheathing will increase the current-carrying capacity of the wire.
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A copper wire of radius 0.5 mm is insulated with a sheathing of thickness 1 mm having a thermal conductivity of 0.5 W/m-K. The outside surface convective heat transfer coefficient is 10 W/m2-K. If the thickness of insulation sheathing is raised by 10 mm, then the electrical current-carrying capacity of the wire willa) increaseb) decreasec) remain the samed) vary depending upon the electrical conductivity of the wireCorrect answer is option 'A'. Can you explain this answer?
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A copper wire of radius 0.5 mm is insulated with a sheathing of thickness 1 mm having a thermal conductivity of 0.5 W/m-K. The outside surface convective heat transfer coefficient is 10 W/m2-K. If the thickness of insulation sheathing is raised by 10 mm, then the electrical current-carrying capacity of the wire willa) increaseb) decreasec) remain the samed) vary depending upon the electrical conductivity of the wireCorrect answer is option 'A'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about A copper wire of radius 0.5 mm is insulated with a sheathing of thickness 1 mm having a thermal conductivity of 0.5 W/m-K. The outside surface convective heat transfer coefficient is 10 W/m2-K. If the thickness of insulation sheathing is raised by 10 mm, then the electrical current-carrying capacity of the wire willa) increaseb) decreasec) remain the samed) vary depending upon the electrical conductivity of the wireCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A copper wire of radius 0.5 mm is insulated with a sheathing of thickness 1 mm having a thermal conductivity of 0.5 W/m-K. The outside surface convective heat transfer coefficient is 10 W/m2-K. If the thickness of insulation sheathing is raised by 10 mm, then the electrical current-carrying capacity of the wire willa) increaseb) decreasec) remain the samed) vary depending upon the electrical conductivity of the wireCorrect answer is option 'A'. Can you explain this answer?.
A copper wire of radius 0.5 mm is insulated with a sheathing of thickness 1 mm having a thermal conductivity of 0.5 W/m-K. The outside surface convective heat transfer coefficient is 10 W/m2-K. If the thickness of insulation sheathing is raised by 10 mm, then the electrical current-carrying capacity of the wire willa) increaseb) decreasec) remain the samed) vary depending upon the electrical conductivity of the wireCorrect answer is option 'A'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about A copper wire of radius 0.5 mm is insulated with a sheathing of thickness 1 mm having a thermal conductivity of 0.5 W/m-K. The outside surface convective heat transfer coefficient is 10 W/m2-K. If the thickness of insulation sheathing is raised by 10 mm, then the electrical current-carrying capacity of the wire willa) increaseb) decreasec) remain the samed) vary depending upon the electrical conductivity of the wireCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A copper wire of radius 0.5 mm is insulated with a sheathing of thickness 1 mm having a thermal conductivity of 0.5 W/m-K. The outside surface convective heat transfer coefficient is 10 W/m2-K. If the thickness of insulation sheathing is raised by 10 mm, then the electrical current-carrying capacity of the wire willa) increaseb) decreasec) remain the samed) vary depending upon the electrical conductivity of the wireCorrect answer is option 'A'. Can you explain this answer?.
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