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For the radiation between two infinite parallel planes of emissivity respectively, which one of the following is the expression for emissivity factor or equivalent emissivity?
  • a)
    ε1ε2
  • b)
  • c)
  • d)
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
For the radiation between two infinite parallel planes of emissivity r...
The equivalent thermal resistance between two gray bodies is given by
Rth = 1-ε1/A1ε1+1/A1F12+1-ε2/A2ε2
Now for infinite parallel panes, F12 =1
A1 = A2 = A
For unit area, A = 1 m2
Rth = 1/ε1+1/ε2-1
Hence equivalent emissivity
Εe = 1/Rth
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Most Upvoted Answer
For the radiation between two infinite parallel planes of emissivity r...
The equivalent thermal resistance between two gray bodies is given by
Rth = 1-ε1/A1ε1+1/A1F12+1-ε2/A2ε2
Now for infinite parallel panes, F12 =1
A1 = A2 = A
For unit area, A = 1 m2
Rth = 1/ε1+1/ε2-1
Hence equivalent emissivity
Εe = 1/Rth
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Community Answer
For the radiation between two infinite parallel planes of emissivity r...
The equivalent thermal resistance between two gray bodies is given by
Rth = 1-ε1/A1ε1+1/A1F12+1-ε2/A2ε2
Now for infinite parallel panes, F12 =1
A1 = A2 = A
For unit area, A = 1 m2
Rth = 1/ε1+1/ε2-1
Hence equivalent emissivity
Εe = 1/Rth
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For the radiation between two infinite parallel planes of emissivity respectively, which one of the following is the expression for emissivity factor or equivalent emissivity?a)ε1ε2b)c)d)Correct answer is option 'D'. Can you explain this answer?
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