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Two very large parallel plates separated by vacuum are maintained at uniform temperatures T1= 750K & T2=500K and have emissivities ε1= 0.85 and ε2 = 0.7 respectively. If a thin aluminium sheet with same emissivity on both sides is placed in between the plates, the rate of heat transfer between the plates reduces by 90%. The emissivity of aluminium sheet is given as
  • a)
    0.07
  • b)
    0.10
  • c)
    0.13
  • d)
    0.16
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Two very large parallel plates separated by vacuum are maintained at u...
By thermal circuits,
Q ∝ 1/R
Where R is resistance to radiation heat exchange between the surfaces.
When there is no sheet between the plates
T1 = 750 K T2 = 500 K
ε1 = 0.85 ε20.7
R1 = 1-ε1/Aε1+1/A+1-ε2/Aε2
R1 = 1-0.85/0.854A+1/A+1-0.7/0.7A
R1 = 1.605/A
When a sheet is placed between the surfaces
Where εs is the emissivity of single shield
surface
∴ R2 = 2.605/A+2(1-εs)/Aεs
∴ Q2/Q1 = R1/R2
It is given that by introducing the sheet in between the plates reduces the heat exchange by 90%
∴ Q2/Q1 = 0.1
∴ R1/R2 = 0.1
∴ 1.605 = 0.2605 + 0.2 (1-εs)/εs
6.7225 εs = 1-εs
εs = 0.1295
εs ≃ 0.13
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Most Upvoted Answer
Two very large parallel plates separated by vacuum are maintained at u...
And T2= 300K. The distance between the plates is 2mm. Find the net rate of heat transfer per unit area between the plates due to radiation.

We can use the Stefan-Boltzmann law to find the heat transfer per unit area between the plates due to radiation:

Q = σA(T1^4 - T2^4)

where σ is the Stefan-Boltzmann constant (5.67 x 10^-8 W/m^2K^4), A is the area of one plate, and T1 and T2 are the temperatures of the plates.

First, we need to find the area of one plate:

A = length x width = 1m x 1m = 1m^2

Next, we can plug in the values and solve for Q:

Q = 5.67 x 10^-8 x 1 x (750^4 - 300^4)
Q = 630.3 W/m^2

Therefore, the net rate of heat transfer per unit area between the plates due to radiation is 630.3 W/m^2.
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Two very large parallel plates separated by vacuum are maintained at uniform temperatures T1= 750K & T2=500K and have emissivities ε1= 0.85 and ε2 = 0.7 respectively. If a thin aluminium sheet with same emissivity on both sides is placed in between the plates, the rate of heat transfer between the plates reduces by 90%. The emissivity of aluminium sheet is given asa)0.07b)0.10c)0.13d)0.16Correct answer is option 'C'. Can you explain this answer?
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