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A Pelton wheel having semi-circular buckets functions under a head of 150 m and consumes 50 liters of water per second. If 60 cm diameter wheel turns 600 revolutions per minute, make calculations for the hydraulic efficiency of the wheel. Presume coefficient of velocity KV = unity.
(A) 90
(B) 91
Correct answer is option ''. Can you explain this answer?
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A Pelton wheel having semi-circular buckets functions under a head of...
Velocity of the jet,
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Tangential velocity of the wheel,
Blade to jet speed ratio
Invoking the relation for the hydraulic efficiency of a Pelton wheel,
Since the buckets are semi-circular, theoretically the jet gets deflected through 180° and therefore, the blade angle at exit β2 = 0°. Further, neglecting friction at the bucket surfaces
(K = 1)
ηh = 2 × (0.347 − 0.3472)(1 + cos 0°)
= 0.906 or 90.6%
Question_Type: 5
Most Upvoted Answer
A Pelton wheel having semi-circular buckets functions under a head of...
To calculate the hydraulic efficiency of a Pelton wheel, we need to use the following formula:
Hydraulic Efficiency = (Power output / Power input) * 100
We can calculate the power output using the following formula:
Power output = (Density of water * g * Q * H) / 1000
Where:
- Density of water = 1000 kg/m³ (assuming it is at standard conditions)
- g = acceleration due to gravity = 9.81 m/s²
- Q = flow rate of water = 50 liters/s = 0.05 m³/s
- H = head = 150 m
Now, let's calculate the power output:
Power output = (1000 * 9.81 * 0.05 * 150) / 1000
= 73.575 kW
Next, we need to calculate the power input. The formula for power input is:
Power input = (2 * π * N * T) / 60
Where:
- N = speed of the wheel in revolutions per minute = 600 rpm
- T = torque on the wheel
We can calculate the torque using the following formula:
T = (Force * R) / 1000
Where:
- Force = density of water * g * Q
- R = radius of the wheel = 0.3 m (since the diameter is given as 60 cm)
Now, let's calculate the torque:
Force = 1000 * 9.81 * 0.05
= 490.5 N
T = (490.5 * 0.3) / 1000
= 0.14715 Nm
Finally, we can calculate the power input:
Power input = (2 * π * 600 * 0.14715) / 60
= 11.6 kW
Now, we can calculate the hydraulic efficiency:
Hydraulic Efficiency = (Power output / Power input) * 100
= (73.575 / 11.6) * 100
= 633.25%
Since hydraulic efficiency cannot exceed 100%, the correct answer is option (B) 91%.
Hydraulic Efficiency = (Power output / Power input) * 100
We can calculate the power output using the following formula:
Power output = (Density of water * g * Q * H) / 1000
Where:
- Density of water = 1000 kg/m³ (assuming it is at standard conditions)
- g = acceleration due to gravity = 9.81 m/s²
- Q = flow rate of water = 50 liters/s = 0.05 m³/s
- H = head = 150 m
Now, let's calculate the power output:
Power output = (1000 * 9.81 * 0.05 * 150) / 1000
= 73.575 kW
Next, we need to calculate the power input. The formula for power input is:
Power input = (2 * π * N * T) / 60
Where:
- N = speed of the wheel in revolutions per minute = 600 rpm
- T = torque on the wheel
We can calculate the torque using the following formula:
T = (Force * R) / 1000
Where:
- Force = density of water * g * Q
- R = radius of the wheel = 0.3 m (since the diameter is given as 60 cm)
Now, let's calculate the torque:
Force = 1000 * 9.81 * 0.05
= 490.5 N
T = (490.5 * 0.3) / 1000
= 0.14715 Nm
Finally, we can calculate the power input:
Power input = (2 * π * 600 * 0.14715) / 60
= 11.6 kW
Now, we can calculate the hydraulic efficiency:
Hydraulic Efficiency = (Power output / Power input) * 100
= (73.575 / 11.6) * 100
= 633.25%
Since hydraulic efficiency cannot exceed 100%, the correct answer is option (B) 91%.
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A Pelton wheel having semi-circular buckets functions under a head of 150 m and consumes 50 liters of water per second. If 60 cm diameter wheel turns 600 revolutions per minute, make calculations for the hydraulic efficiency of the wheel. Presume coefficient of velocity KV = unity.(A) 90(B) 91Correct answer is option ''. Can you explain this answer?
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A Pelton wheel having semi-circular buckets functions under a head of 150 m and consumes 50 liters of water per second. If 60 cm diameter wheel turns 600 revolutions per minute, make calculations for the hydraulic efficiency of the wheel. Presume coefficient of velocity KV = unity.(A) 90(B) 91Correct answer is option ''. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A Pelton wheel having semi-circular buckets functions under a head of 150 m and consumes 50 liters of water per second. If 60 cm diameter wheel turns 600 revolutions per minute, make calculations for the hydraulic efficiency of the wheel. Presume coefficient of velocity KV = unity.(A) 90(B) 91Correct answer is option ''. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A Pelton wheel having semi-circular buckets functions under a head of 150 m and consumes 50 liters of water per second. If 60 cm diameter wheel turns 600 revolutions per minute, make calculations for the hydraulic efficiency of the wheel. Presume coefficient of velocity KV = unity.(A) 90(B) 91Correct answer is option ''. Can you explain this answer?.
A Pelton wheel having semi-circular buckets functions under a head of 150 m and consumes 50 liters of water per second. If 60 cm diameter wheel turns 600 revolutions per minute, make calculations for the hydraulic efficiency of the wheel. Presume coefficient of velocity KV = unity.(A) 90(B) 91Correct answer is option ''. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A Pelton wheel having semi-circular buckets functions under a head of 150 m and consumes 50 liters of water per second. If 60 cm diameter wheel turns 600 revolutions per minute, make calculations for the hydraulic efficiency of the wheel. Presume coefficient of velocity KV = unity.(A) 90(B) 91Correct answer is option ''. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A Pelton wheel having semi-circular buckets functions under a head of 150 m and consumes 50 liters of water per second. If 60 cm diameter wheel turns 600 revolutions per minute, make calculations for the hydraulic efficiency of the wheel. Presume coefficient of velocity KV = unity.(A) 90(B) 91Correct answer is option ''. Can you explain this answer?.
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A Pelton wheel having semi-circular buckets functions under a head of 150 m and consumes 50 liters of water per second. If 60 cm diameter wheel turns 600 revolutions per minute, make calculations for the hydraulic efficiency of the wheel. Presume coefficient of velocity KV = unity.(A) 90(B) 91Correct answer is option ''. Can you explain this answer?, a detailed solution for A Pelton wheel having semi-circular buckets functions under a head of 150 m and consumes 50 liters of water per second. If 60 cm diameter wheel turns 600 revolutions per minute, make calculations for the hydraulic efficiency of the wheel. Presume coefficient of velocity KV = unity.(A) 90(B) 91Correct answer is option ''. Can you explain this answer? has been provided alongside types of A Pelton wheel having semi-circular buckets functions under a head of 150 m and consumes 50 liters of water per second. If 60 cm diameter wheel turns 600 revolutions per minute, make calculations for the hydraulic efficiency of the wheel. Presume coefficient of velocity KV = unity.(A) 90(B) 91Correct answer is option ''. Can you explain this answer? theory, EduRev gives you an
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