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A 220v series motor taking a current of 40A.Resistance of armature is 0.5ohm and resistance of series field is 0.25. Calculate a) Voltage at brushes. b) Back Emf c) Power wasted in armature d) Power wasted in series field?
Most Upvoted Answer
A 220v series motor taking a current of 40A.Resistance of armature is ...
Back emf=220-40(0.25+0.5)=190
voltage at brushes =220-(0.25×40)=210
power loss in armature resistance=40^2*0.5=800
power loss in series field=40^2*0.25=400
voltage at brushes =220-(0.25×40)=210
power loss in armature resistance=40^2*0.5=800
power loss in series field=40^2*0.25=400
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A 220v series motor taking a current of 40A.Resistance of armature is ...
Calculation of Voltage, Back Emf and Power Wastage in a Series Motor
Given:
Voltage (V) = 220 V
Current (I) = 40 A
Armature Resistance (Ra) = 0.5 Ω
Series Field Resistance (Rs) = 0.25 Ω
a) Calculation of Voltage at Brushes:
The voltage at the brushes is given as:
Vbrushes = V - I(Ra + Rs)
= 220 - 40(0.5 + 0.25)
= 205 V
Therefore, the voltage at the brushes is 205 V.
b) Calculation of Back Emf:
The back emf of the motor is given as:
Eb = Vbrushes - I(Ra)
= 205 - 40(0.5)
= 185 V
Therefore, the back emf of the motor is 185 V.
c) Calculation of Power Wastage in Armature:
The power wastage in the armature is given as:
Parmature = I^2(Ra)
= 40^2(0.5)
= 800 W
Therefore, the power wastage in the armature is 800 W.
d) Calculation of Power Wastage in Series Field:
The power wastage in the series field is given as:
Pseries field = I^2(Rs)
= 40^2(0.25)
= 400 W
Therefore, the power wastage in the series field is 400 W.
Conclusion:
Thus, the voltage at the brushes is 205 V, the back emf of the motor is 185 V, the power wastage in the armature is 800 W and the power wastage in the series field is 400 W.
Given:
Voltage (V) = 220 V
Current (I) = 40 A
Armature Resistance (Ra) = 0.5 Ω
Series Field Resistance (Rs) = 0.25 Ω
a) Calculation of Voltage at Brushes:
The voltage at the brushes is given as:
Vbrushes = V - I(Ra + Rs)
= 220 - 40(0.5 + 0.25)
= 205 V
Therefore, the voltage at the brushes is 205 V.
b) Calculation of Back Emf:
The back emf of the motor is given as:
Eb = Vbrushes - I(Ra)
= 205 - 40(0.5)
= 185 V
Therefore, the back emf of the motor is 185 V.
c) Calculation of Power Wastage in Armature:
The power wastage in the armature is given as:
Parmature = I^2(Ra)
= 40^2(0.5)
= 800 W
Therefore, the power wastage in the armature is 800 W.
d) Calculation of Power Wastage in Series Field:
The power wastage in the series field is given as:
Pseries field = I^2(Rs)
= 40^2(0.25)
= 400 W
Therefore, the power wastage in the series field is 400 W.
Conclusion:
Thus, the voltage at the brushes is 205 V, the back emf of the motor is 185 V, the power wastage in the armature is 800 W and the power wastage in the series field is 400 W.
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A 220v series motor taking a current of 40A.Resistance of armature is 0.5ohm and resistance of series field is 0.25. Calculate a) Voltage at brushes. b) Back Emf c) Power wasted in armature d) Power wasted in series field?
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A 220v series motor taking a current of 40A.Resistance of armature is 0.5ohm and resistance of series field is 0.25. Calculate a) Voltage at brushes. b) Back Emf c) Power wasted in armature d) Power wasted in series field? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 220v series motor taking a current of 40A.Resistance of armature is 0.5ohm and resistance of series field is 0.25. Calculate a) Voltage at brushes. b) Back Emf c) Power wasted in armature d) Power wasted in series field? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 220v series motor taking a current of 40A.Resistance of armature is 0.5ohm and resistance of series field is 0.25. Calculate a) Voltage at brushes. b) Back Emf c) Power wasted in armature d) Power wasted in series field?.
A 220v series motor taking a current of 40A.Resistance of armature is 0.5ohm and resistance of series field is 0.25. Calculate a) Voltage at brushes. b) Back Emf c) Power wasted in armature d) Power wasted in series field? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 220v series motor taking a current of 40A.Resistance of armature is 0.5ohm and resistance of series field is 0.25. Calculate a) Voltage at brushes. b) Back Emf c) Power wasted in armature d) Power wasted in series field? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 220v series motor taking a current of 40A.Resistance of armature is 0.5ohm and resistance of series field is 0.25. Calculate a) Voltage at brushes. b) Back Emf c) Power wasted in armature d) Power wasted in series field?.
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