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The logarithmic mean temperature difference (LMTD) of a counter flow heat exchanger is 20°C. The cold fluid enters at 20°C and the hot fluid enters at 100°C. Mass flow rate of the cold fluid is twice that of the hot fluid. Specific heat at constant pressure of the hot fluid is twice that of the cold fluid. The exit temperature of the cold fluid
[2008]
  • a)
    is 40°C
  • b)
    is 60°C
  • c)
    is 80°C
  • d)
    cannot be determined
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The logarithmic mean temperature difference (LMTD) of a counter flow h...
θ1 = θ2
∴ θm = 20°C
Th1 – Tc2 = 20°C
100 – Tc2 = 20°C
Tc2 = 80°C
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Most Upvoted Answer
The logarithmic mean temperature difference (LMTD) of a counter flow h...
The logarithmic mean temperature difference (LMTD) of a counter flow heat exchanger is a measure of the overall temperature difference between the hot and cold fluids as they flow through the exchanger. It is used to calculate the heat transfer rate in the exchanger.

In this case, the LMTD is given as 20. The LMTD can be calculated using the following formula:

LMTD = (ΔT1 - ΔT2) / ln(ΔT1 / ΔT2)

Where:
ΔT1 = temperature difference between the hot fluid inlet and hot fluid outlet
ΔT2 = temperature difference between the cold fluid inlet and cold fluid outlet

To calculate the actual temperature differences ΔT1 and ΔT2, more information about the specific heat exchanger is needed. The LMTD alone is not sufficient to determine the temperature differences between the fluids.
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The logarithmic mean temperature difference (LMTD) of a counter flow heat exchanger is 20°C. The cold fluid enters at 20°C and the hot fluid enters at 100°C. Mass flow rate of the cold fluid is twice that of the hot fluid. Specific heat at constant pressure of the hot fluid is twice that of the cold fluid. The exit temperature of the cold fluid[2008]a)is 40°Cb)is 60°Cc)is 80°Cd)cannot be determinedCorrect answer is option 'C'. Can you explain this answer?
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