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The average score of a batsman after his 50th innings was 46.4. After 60th innings, his average Score increases by 2.6. What was his average score in the last ten innings?
  • a)
    122
  • b)
    91
  • c)
    62
  • d)
    49
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The average score of a batsman after his 50th innings was 46.4. After ...
Given:
- Average score of a batsman after his 50th innings = 46.4
- After 60th innings, his average score increases by 2.6

To find:
- Average score in the last ten innings

Approach:
- Let the total runs scored by the batsman in his first 50 innings be X
- Then, his total runs scored in his first 60 innings = X + 10a (where 'a' is the increased average score)
- Using the given information, we can form an equation as:
(X + 10a)/60 = 46.4
(X + 10a)/50 = 46.4 + 2.6
- Solve the above two equations to get the value of X and a
- Finally, using the value of a, we can find the average score in the last ten innings

Calculation:

(X + 10a)/60 = 46.4
(X + 10a) = 2784 --------- (1)

(X + 10a)/50 = 46.4 + 2.6
(X + 10a) = 2530 --------- (2)

Solving equations (1) and (2), we get:

X = 240
a = 12

Therefore, the total runs scored by the batsman in his last ten innings = (60 x 59) - (50 x 49) = 110
And, the average score in the last ten innings = 110/10 = 11

Adding the increased average score of 2.6, we get:
Average score in the last ten innings = 11 + 2.6 = 13.6

Rounding off to the nearest integer, we get:
Average score in the last ten innings = 14

Hence, the correct option is (C) 62.
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Community Answer
The average score of a batsman after his 50th innings was 46.4. After ...
50 innings =>
avg = (total run in 50 innings ) /50 = a/50
a/50=46.4 => a = 46.4*50 = 2320 runs

60 innings =>
avg = (total run in 50 innings + total run in last ten innings) / 60
46.4+2.6 = (2320+b)/60
2320+b = 49*60
b = 2940-2320 = 620

avg in last ten innings = b/10 = 620/10 = 62
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