The number of ions formed on dissolving one molecule of FeSO4(NH4)2SO4.6H2O in water is 1 3 5 7?

Question

Answer

Number of ions formed on dissolving one molecule of FeSO₄(NH₄)₂SO₄.6H₂O in water:

When one molecule of FeSO₄(NH₄)₂SO₄.6H₂O is dissolved in water, it dissociates into several ions. Let's break down the compound and calculate the number of ions formed.

FeSO₄(NH₄)₂SO₄.6H₂O:
- The compound consists of Fe²⁺ ions, SO₄^2- ions, and (NH₄)⁺ ions.
- Additionally, the compound also contains 6 water molecules (H₂O), which can dissociate into H⁺ and OH^- ions.

Dissociation of FeSO₄(NH₄)₂SO₄.6H₂O:
1. FeSO₄(NH₄)₂SO₄.6H₂O → Fe²⁺ + SO₄^2- + 2(NH₄)⁺ + 2SO₄^2- + 6H₂O
2. Fe²⁺ + SO₄^2- + 2(NH₄)⁺ + 2SO₄^2- + 6H₂O → Fe²⁺ + SO₄^2- + 2(NH₄)⁺ + 2SO₄^2- + 6H⁺ + 6OH^-

Number of ions formed:
From the above dissociation reaction, we can count the number of ions formed:
- Fe²⁺ ion: 1 ion
- SO₄^2- ion: 2 ions
- (NH₄)⁺ ion: 2 ions
- H⁺ ion: 6 ions
- OH^- ion: 6 ions

Total number of ions:

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