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A parachutist with mass m=80kg is undergoing free fall. The drag force applied on him is fpp=kv² where v is the velocity measured relative to the air the constant k=0.27 Ns²/m² is given find (a) the terminal velocity?
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A parachutist with mass m=80kg is undergoing free fall. The drag force...
Terminal Velocity of a Parachutist Undergoing Free Fall

Given:

  • Mass of the parachutist, m = 80 kg

  • Drag force applied on the parachutist, fpp = kv², where k = 0.27 Ns²/m²



Formula:

  • Weight of the parachutist, W = mg, where g = acceleration due to gravity = 9.8 m/s²

  • Net force acting on the parachutist, Fnet = W - fpp

  • At terminal velocity, Fnet = 0

  • Therefore, W = fpp at terminal velocity

  • Using W = mg and fpp = kv², we get:


mg = kv²

v = √(mg/k)


Solution:

  • Substituting the given values in the formula, we get:


v = √(80 x 9.8 / 0.27) = 32.15 m/s


  • Therefore, the terminal velocity of the parachutist is 32.15 m/s.

  • The terminal velocity is the maximum velocity that the parachutist can attain while undergoing free fall under the influence of air resistance.

  • At terminal velocity, the net force acting on the parachutist is zero, which means that the weight of the parachutist is balanced by the air resistance.

  • Thus, the parachutist stops accelerating and continues to fall at a constant velocity.

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A parachutist with mass m=80kg is undergoing free fall. The drag force...
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A parachutist with mass m=80kg is undergoing free fall. The drag force applied on him is fpp=kv² where v is the velocity measured relative to the air the constant k=0.27 Ns²/m² is given find (a) the terminal velocity?
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A parachutist with mass m=80kg is undergoing free fall. The drag force applied on him is fpp=kv² where v is the velocity measured relative to the air the constant k=0.27 Ns²/m² is given find (a) the terminal velocity? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A parachutist with mass m=80kg is undergoing free fall. The drag force applied on him is fpp=kv² where v is the velocity measured relative to the air the constant k=0.27 Ns²/m² is given find (a) the terminal velocity? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A parachutist with mass m=80kg is undergoing free fall. The drag force applied on him is fpp=kv² where v is the velocity measured relative to the air the constant k=0.27 Ns²/m² is given find (a) the terminal velocity?.
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