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One kilogram of a perfect gas at 150C and 100 KPa is heated to 450C by (i) constant pressure process and (ii) a constant volume process. Cp=1.042 KJ/Kg-K; R=0.2968 KJ/Kg-K. Heat added in the constant volume (Qv) and constant process (Qp) processes are?
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One kilogram of a perfect gas at 150C and 100 KPa is heated to 450C by...
Answer:


Given:

Mass of gas, m = 1 kg

Initial temperature, T1 = 150°C = 423 K

Initial pressure, P1 = 100 kPa

Final temperature, T2 = 450°C = 723 K

Specific heat capacity at constant pressure, Cp = 1.042 kJ/kg-K

Universal gas constant, R = 0.2968 kJ/kg-K


Constant Pressure Process:

In a constant pressure process, the pressure remains constant while the volume changes. The heat added during a constant pressure process is given by the formula:
Qp = m*Cp*(T2-T1)
Where Qp is the heat added, m is the mass of the gas, Cp is the specific heat capacity at constant pressure, T1 is the initial temperature, and T2 is the final temperature.

Substituting the given values, we get:
Qp = 1*1.042*(723-423)
Qp = 311.94 kJ

Therefore, the heat added in the constant pressure process is 311.94 kJ.

Constant Volume Process:

In a constant volume process, the volume remains constant while the pressure changes. The heat added during a constant volume process is given by the formula:
Qv = m*Cv*(T2-T1)
Where Qv is the heat added, m is the mass of the gas, Cv is the specific heat capacity at constant volume, T1 is the initial temperature, and T2 is the final temperature.

The specific heat capacity at constant volume, Cv can be calculated using the formula:
Cv = Cp - R
Where R is the universal gas constant.

Substituting the given values, we get:
Cv = 1.042 - 0.2968
Cv = 0.7452 kJ/kg-K

Substituting the values of Cv and the given values, we get:
Qv = 1*0.7452*(723-423)
Qv = 223.56 kJ

Therefore, the heat added in the constant volume process is 223.56 kJ.

Explanation:

The given problem involves finding the heat added in a constant pressure process and a constant volume process. In a constant pressure process, the pressure remains constant while the volume changes. The heat added during a constant pressure process is given by the formula Qp = m*Cp*(T2-T1). In a constant volume process, the volume remains constant while the pressure changes. The heat added during a constant volume process is given by the formula Qv = m*Cv*(T2-T1), where Cv is the specific heat capacity at constant volume. The value of Cv can be calculated using the formula Cv = Cp - R, where R is the universal gas constant. By substituting the given values in the respective formulas, we get the heat added in the constant pressure process and the constant volume process.
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One kilogram of a perfect gas at 150C and 100 KPa is heated to 450C by (i) constant pressure process and (ii) a constant volume process. Cp=1.042 KJ/Kg-K; R=0.2968 KJ/Kg-K. Heat added in the constant volume (Qv) and constant process (Qp) processes are?
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One kilogram of a perfect gas at 150C and 100 KPa is heated to 450C by (i) constant pressure process and (ii) a constant volume process. Cp=1.042 KJ/Kg-K; R=0.2968 KJ/Kg-K. Heat added in the constant volume (Qv) and constant process (Qp) processes are? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about One kilogram of a perfect gas at 150C and 100 KPa is heated to 450C by (i) constant pressure process and (ii) a constant volume process. Cp=1.042 KJ/Kg-K; R=0.2968 KJ/Kg-K. Heat added in the constant volume (Qv) and constant process (Qp) processes are? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One kilogram of a perfect gas at 150C and 100 KPa is heated to 450C by (i) constant pressure process and (ii) a constant volume process. Cp=1.042 KJ/Kg-K; R=0.2968 KJ/Kg-K. Heat added in the constant volume (Qv) and constant process (Qp) processes are?.
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