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An army contingent of 616 members is to march behind an army band of 32 members in a parade. The two groups are to march in the same number of columns. What is the maximum number of columns in which they can march? 
  • a)
    8
  • b)
    7
  • c)
    6
  • d)
    9
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
An army contingent of 616 members is to march behind an army band of 3...
Maximum number of columns = HCF of 616 and 32 
616 = 23 × 7 × 11
32 = 25
∴ HCF of 616 and 32 =  8
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Most Upvoted Answer
An army contingent of 616 members is to march behind an army band of 3...
According to Euclid's division algorithm
616 = 32×19 + 8
32 = 8× 4 +0
Therefore HCF = 8
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Community Answer
An army contingent of 616 members is to march behind an army band of 3...
To find the maximum number of columns in which the army contingent and the army band can march, we need to find the common factors of 616 and 32. The common factors will represent the possible number of columns.

Prime Factorization of 616:
616 = 2 × 2 × 2 × 7 × 11

Prime Factorization of 32:
32 = 2 × 2 × 2 × 2 × 2

Finding the Common Factors:
The common factors of 616 and 32 are the common prime factors raised to the lowest power they occur in both numbers:

Common Factors = 2 × 2 × 2 = 8

Therefore, the maximum number of columns in which they can march is 8.
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An army contingent of 616 members is to march behind an army band of 32 members in a parade. The two groups are to march in the same number of columns. What is the maximum number of columns in which they can march?a)8b)7c)6d)9Correct answer is option 'A'. Can you explain this answer?
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