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Between 6 PM and 7 PM the minute hand of a clock will be ahead of the hour hand by 3 minutes at
[2015]
- a)6: 15 PM
- b)6: 18 PM
- c)6: 36 PM
- d)6: 48 PM
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
Between 6 PM and 7 PM the minute hand of a clock will be ahead of the ...
Easy way: Between 6-7 the hour hand will be in between 6 (30 min) to 7 (35 min) and the hour hand can be anywhere between (0-60 min) 12-12. For there to be a difference of 3 minutes between the hour and minute hand, the time can only be between 6:27 to 6:38. Therefore, Option C is the answer.
Long Method:
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Long Method:
1 min = 6 degrees
If minute hand is 3 minutes ahead of hour hand, it means angle between the two hands is 18�.
Let the required time be 6:x pm
The minute hand will travel 6x� while hour hand will travel (6*60 + x)*1/2 = (180 + x/2)�
According to available information :
6x - 180 - x/2 = 18
=> 12x - 360 - x = 36
=> 11x = 396
=> x = 396/11 = 36
=> Required time is 6:36 pm
Most Upvoted Answer
Between 6 PM and 7 PM the minute hand of a clock will be ahead of the ...
Explanation:
To solve this problem, we need to remember that the minute hand moves 12 times as fast as the hour hand. Therefore, in 1 hour (or 60 minutes), the minute hand moves 720 degrees, while the hour hand moves 30 degrees.
Let's assume that the time is x minutes past 6 PM.
• At x minutes past 6 PM, the minute hand would be at (720/60)x = 12x degrees from 12 o'clock position.
• At x minutes past 6 PM, the hour hand would be at (30/60)x = 0.5x degrees from 12 o'clock position.
Since the minute hand is ahead of the hour hand by 3 minutes, the minute hand would be 15 degrees (3 minutes * 6 degrees per minute) ahead of the hour hand. Therefore, we can set up the equation:
12x - 0.5x = 15
11.5x = 15
x = 15/11.5
So, the time is approximately 1.30 minutes past 6 PM.
Therefore, the answer is option C, 6:36 PM.
To solve this problem, we need to remember that the minute hand moves 12 times as fast as the hour hand. Therefore, in 1 hour (or 60 minutes), the minute hand moves 720 degrees, while the hour hand moves 30 degrees.
Let's assume that the time is x minutes past 6 PM.
• At x minutes past 6 PM, the minute hand would be at (720/60)x = 12x degrees from 12 o'clock position.
• At x minutes past 6 PM, the hour hand would be at (30/60)x = 0.5x degrees from 12 o'clock position.
Since the minute hand is ahead of the hour hand by 3 minutes, the minute hand would be 15 degrees (3 minutes * 6 degrees per minute) ahead of the hour hand. Therefore, we can set up the equation:
12x - 0.5x = 15
11.5x = 15
x = 15/11.5
So, the time is approximately 1.30 minutes past 6 PM.
Therefore, the answer is option C, 6:36 PM.
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Between 6 PM and 7 PM the minute hand of a clock will be ahead of the hour hand by 3 minutes at[2015]a)6: 15 PMb)6: 18 PMc)6: 36 PMd)6: 48 PMCorrect answer is option 'C'. Can you explain this answer?
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