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The H.C.F of 4 × 27 × 3125, 8 × 9 × 25 × 7 and 16 × 81 × 5 × 11 × 49 is:
  • a)
    180
  • b)
    360
  • c)
    540
  • d)
    1260
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The H.C.F of 4 × 27 × 3125, 8 × 9 × 25 × 7 and 16 × 81 × 5 × 11 × 49 ...
Given,
4 × 27 × 3125
= 22 × 33 × 55
8 × 9 × 25 × 7
= 23 × 32 × 52 × 7
16 × 81 × 5 × 11 × 49
= 24 × 34 × 5 × 11 × 72
∴ H.C.F = 22 × 32 × 5 = 180
Hence, the correct option is (A).
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Most Upvoted Answer
The H.C.F of 4 × 27 × 3125, 8 × 9 × 25 × 7 and 16 × 81 × 5 × 11 × 49 ...
The H.C.F (Highest Common Factor) of three numbers can be found by prime factorizing each number and finding the common factors.

Given numbers are:
1) 4 × 27 × 3125
2) 8 × 9 × 25 × 7
3) 16 × 81 × 5 × 11 × 49

Prime factorizing each number:
1) 4 × 27 × 3125 = 2^2 × 3^3 × 5^5
2) 8 × 9 × 25 × 7 = 2^3 × 3^2 × 5^2 × 7
3) 16 × 81 × 5 × 11 × 49 = 2^4 × 3^4 × 5 × 11 × 7^2

Finding the common factors:
The H.C.F is the product of the common prime factors raised to the lowest powers.

Common Prime Factors:
2, 3, 5, 7, 11

Lowest Powers:
2^2, 3^2, 5, 7

Product:
H.C.F = 2^2 × 3^2 × 5 × 7 = 180

Therefore, the H.C.F of 4 × 27 × 3125, 8 × 9 × 25 × 7, and 16 × 81 × 5 × 11 × 49 is 180.
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