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Positive value of ‘K’ for which the roots at equation 12x^2 Kx 5=0 are in ratio 3:2 is?
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Positive value of ‘K’ for which the roots at equation 12x^2 Kx 5=0 are...
Solution:

Ratio of roots: 3:2
Let the roots be 3a and 2a.
Sum of roots = -b/a = -K/12
3a+2a= -K/12
5a= -K/12
a = -(K/60)

Product of roots = c/a = 5/12K
(3a)(2a) = 5/12K
6a^2 = 5/12K
6[(-K/60)^2] = 5/12K
K^3/10000 = K/1440
K^2 = 14400000
K = + 4000 or - 3600

As K needs to be positive, the value of K is 4000.

Therefore, the positive value of 'K' for which the roots of the equation 12x^2 Kx 5=0 are in the ratio 3:2 is 4000.

Summary:

Given equation: 12x^2 Kx 5=0

Ratio of roots: 3:2

Let the roots be 3a and 2a.

Sum of roots = -K/12

Product of roots = 5/12K

On solving the above equations, K = + 4000 or - 3600

As K needs to be positive, the value of K is 4000.
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Positive value of ‘K’ for which the roots at equation 12x^2 Kx 5=0 are in ratio 3:2 is?
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