Two times a two digit number is 9 times the number obtained by reversi...
On checking the options we find that option (d) satisfies all the conditions i.e., 2 x 81 = 9 x 18. Also sum of the digits of 81 is 9.
Two times a two digit number is 9 times the number obtained by reversi...
To solve this question, we will use algebraic equations to represent the given conditions.
Let's assume the two-digit number to be xy, where x represents the tens digit and y represents the units digit.
According to the first condition, "two times a two-digit number is 9 times the number obtained by reversing the digits," we can write the equation:
2 * (10x + y) = 9 * (10y + x)
Simplifying this equation, we get:
20x + 2y = 90y + 9x
19x = 88y
Dividing both sides by 19, we have:
x = (88/19)y
Since x and y represent digits, x must be a whole number. Therefore, (88/19)y must be a whole number as well.
The only value of y that satisfies this condition is 19 because 19 is the only factor of 19 that divides 88 evenly.
Therefore, y = 19.
Substituting the value of y back into the equation, we can find the value of x:
x = (88/19)(19)
x = 88
Thus, the two-digit number is 88.
Now, let's check if the second condition, "the sum of the digits is 9," is satisfied by the number 88.
Sum of the digits of 88 = 8 + 8 = 16 ≠ 9
Since the sum of the digits is not 9, the number 88 does not satisfy all the given conditions.
Therefore, the correct answer is not among the given options.