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The sum of series 3.5 7 10.5 14 . to17 terms is?
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The sum of series 3.5 7 10.5 14 . to17 terms is?
Sum of Series 3.5 7 10.5 14 to 17 terms
- First, we need to find the common difference of the series. The common difference is the difference between any two consecutive terms in the series.
- Here, the common difference is 3.5. We can find this by subtracting the second term, 7, from the first term, 3.5.
- The formula to find the sum of an arithmetic series is: S = n/2 × (2a + (n-1)d), where S is the sum of the series, n is the number of terms, a is the first term, and d is the common difference.
- Using this formula, we can find the sum of the series up to the 17th term:
S = 17/2 × (2(3.5) + (17-1)3.5)
S = 17/2 × (7 + 48.3)
S = 17/2 × 55.3
S = 470.95
Therefore, the sum of the series 3.5 7 10.5 14 to 17 terms is 470.95.
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The sum of series 3.5 7 10.5 14 . to17 terms is?
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The sum of series 3.5 7 10.5 14 . to17 terms is? for CA Foundation 2025 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about The sum of series 3.5 7 10.5 14 . to17 terms is? covers all topics & solutions for CA Foundation 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The sum of series 3.5 7 10.5 14 . to17 terms is?.
The sum of series 3.5 7 10.5 14 . to17 terms is? for CA Foundation 2025 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about The sum of series 3.5 7 10.5 14 . to17 terms is? covers all topics & solutions for CA Foundation 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The sum of series 3.5 7 10.5 14 . to17 terms is?.
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