P equal to 2 square 3 square and q square where Q is a prime less than...
Introduction:
In this question, we are given the prime factorization representation of a number p, which is P = 2^2 x 3^2 x q^2, where q is a prime less than 7. We need to find the value of p.
Solution:
To find the value of p, we need to multiply all the factors of P. Therefore, we have:
P = 2^2 x 3^2 x q^2
P = 4 x 9 x q^2
P = 36q^2
Now, we need to find the value of q. We know that q is a prime less than 7. Therefore, we have the following possibilities for q:
q = 2, 3, 5
If q = 2, then P = 36 x 2^2 = 144
If q = 3, then P = 36 x 3^2 = 324
If q = 5, then P = 36 x 5^2 = 900
However, we know that P is a two-digit number since q is a prime less than 7. Therefore, q cannot be 5. Thus, we have two possibilities for P:
P = 144 or P = 324
Conclusion:
Therefore, the value of P is either 144 or 324, depending on the value of q.
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