A sells an article to B at a profit of 10% B sells the article back t...
Solution:
Given, A sells an article to B at a profit of 10%. Let the cost price of the article for A be Rs. x.
Selling price of the article for A = x + 10% of x = 1.1x.
B sells the same article back to A at a loss of 10%. Let the selling price of the article for B be Rs. y.
Cost price of the article for B = y + 10% of y = 1.1y.
As B sells the article back to A, the selling price of B becomes the cost price for A.
So, 1.1y = selling price of the article for A.
Now, A buys the article back at a loss of 10%.
So, A sells the article for 0.9(1.1y) = 0.99y.
Profit or Loss for A:
Profit or Loss = Selling price - Cost price
Profit or Loss = 0.99y - 1.1x
As given, A sells the article to B at a profit of 10%.
So, 1.1x = selling price of the article for A
Profit or Loss = 0.99y - 1.1x
Profit or Loss = 0.99y - 1.1(1.1y/1.1)
Profit or Loss = 0.99y - y
Profit or Loss = -0.01y
Therefore, A makes a profit of 1% (not 11% as mentioned in option B) when B sells the article back to A at a loss of 10%. Hence, option B is the correct answer.
A sells an article to B at a profit of 10% B sells the article back t...
Let CP was 100 for A originally
A sells article to B at 10% profit,
CP for B = 100 + 10% of 100 = 110
Now, B sells it A again with loss 10%
Now, CP for A this time = 110 - 10% of 110 = 99
A makes Profit = 110 - 99 = 11
= 11%
Hence, the correct option is (B).