UPSC Exam  >  UPSC Questions  >  In an ideal Brayton cycle , air from the atmo... Start Learning for Free
In an ideal Brayton cycle , air from the atmosphere at 1 atm, 300 K is compressed to 6 atm and the maximum cycle temperature is limited to 1100 K by using large air fuel ratio. If the heat supply is 100 MW, find the thermal efficiency of the cycle and also the work ratio.?
Most Upvoted Answer
In an ideal Brayton cycle , air from the atmosphere at 1 atm, 300 K is...
Brayton Cycle

The Brayton cycle is a thermodynamic cycle used in gas turbine engines and some air compressor systems. It consists of four processes: isentropic compression, constant-pressure heat addition, isentropic expansion, and constant-pressure heat rejection.

Given Parameters
- Inlet Pressure (P1) = 1 atm
- Inlet Temperature (T1) = 300 K
- Outlet Pressure (P2) = 6 atm
- Maximum Cycle Temperature (T3) = 1100 K
- Heat Supply (Qin) = 100 MW

Thermal Efficiency

The thermal efficiency of the Brayton cycle can be calculated using the formula:

η = (Net Work Output / Heat Supply) = (Wturbine - Wcompressor) / Qin

Where,
- Wturbine = Work done by the turbine
- Wcompressor = Work done by the compressor

Calculating Wcompressor

The compression process is isentropic, so we can use the isentropic compression equation to calculate the work done by the compressor:

Wcompressor = C_p * T1 * [(P2/P1)^((γ-1)/γ) - 1]

Where,
- C_p = Specific heat at constant pressure
- γ = Ratio of specific heats

Substituting the given values, we get Wcompressor = 192.5 MW

Calculating Wturbine

The expansion process is also isentropic, so we can use the isentropic expansion equation to calculate the work done by the turbine:

Wturbine = C_p * T3 * [(P2/P1)^((γ-1)/γ) - 1]

Substituting the given values, we get Wturbine = 370.7 MW

Calculating Thermal Efficiency

Substituting the values of Wcompressor and Wturbine in the formula of thermal efficiency, we get:

η = (Wturbine - Wcompressor) / Qin = (370.7 - 192.5) / 100 = 178.2 / 100 = 1.782

Therefore, the thermal efficiency of the cycle is 1.782 or 178.2%.

Work Ratio

The work ratio is defined as the ratio of the turbine work to the compressor work:

WR = Wturbine / Wcompressor = 370.7 / 192.5 = 1.925

Therefore, the work ratio of the cycle is 1.925.
Community Answer
In an ideal Brayton cycle , air from the atmosphere at 1 atm, 300 K is...
Rh4j
Explore Courses for UPSC exam

Top Courses for UPSC

In an ideal Brayton cycle , air from the atmosphere at 1 atm, 300 K is compressed to 6 atm and the maximum cycle temperature is limited to 1100 K by using large air fuel ratio. If the heat supply is 100 MW, find the thermal efficiency of the cycle and also the work ratio.?
Question Description
In an ideal Brayton cycle , air from the atmosphere at 1 atm, 300 K is compressed to 6 atm and the maximum cycle temperature is limited to 1100 K by using large air fuel ratio. If the heat supply is 100 MW, find the thermal efficiency of the cycle and also the work ratio.? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about In an ideal Brayton cycle , air from the atmosphere at 1 atm, 300 K is compressed to 6 atm and the maximum cycle temperature is limited to 1100 K by using large air fuel ratio. If the heat supply is 100 MW, find the thermal efficiency of the cycle and also the work ratio.? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an ideal Brayton cycle , air from the atmosphere at 1 atm, 300 K is compressed to 6 atm and the maximum cycle temperature is limited to 1100 K by using large air fuel ratio. If the heat supply is 100 MW, find the thermal efficiency of the cycle and also the work ratio.?.
Solutions for In an ideal Brayton cycle , air from the atmosphere at 1 atm, 300 K is compressed to 6 atm and the maximum cycle temperature is limited to 1100 K by using large air fuel ratio. If the heat supply is 100 MW, find the thermal efficiency of the cycle and also the work ratio.? in English & in Hindi are available as part of our courses for UPSC. Download more important topics, notes, lectures and mock test series for UPSC Exam by signing up for free.
Here you can find the meaning of In an ideal Brayton cycle , air from the atmosphere at 1 atm, 300 K is compressed to 6 atm and the maximum cycle temperature is limited to 1100 K by using large air fuel ratio. If the heat supply is 100 MW, find the thermal efficiency of the cycle and also the work ratio.? defined & explained in the simplest way possible. Besides giving the explanation of In an ideal Brayton cycle , air from the atmosphere at 1 atm, 300 K is compressed to 6 atm and the maximum cycle temperature is limited to 1100 K by using large air fuel ratio. If the heat supply is 100 MW, find the thermal efficiency of the cycle and also the work ratio.?, a detailed solution for In an ideal Brayton cycle , air from the atmosphere at 1 atm, 300 K is compressed to 6 atm and the maximum cycle temperature is limited to 1100 K by using large air fuel ratio. If the heat supply is 100 MW, find the thermal efficiency of the cycle and also the work ratio.? has been provided alongside types of In an ideal Brayton cycle , air from the atmosphere at 1 atm, 300 K is compressed to 6 atm and the maximum cycle temperature is limited to 1100 K by using large air fuel ratio. If the heat supply is 100 MW, find the thermal efficiency of the cycle and also the work ratio.? theory, EduRev gives you an ample number of questions to practice In an ideal Brayton cycle , air from the atmosphere at 1 atm, 300 K is compressed to 6 atm and the maximum cycle temperature is limited to 1100 K by using large air fuel ratio. If the heat supply is 100 MW, find the thermal efficiency of the cycle and also the work ratio.? tests, examples and also practice UPSC tests.
Explore Courses for UPSC exam

Top Courses for UPSC

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev