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An electron in an atom drops from an energy leveal at -1.1×10-18 J to an energy level at -2.4×10-18 J. The wave associated with the emitted photon has a frequency?
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An electron in an atom drops from an energy leveal at -1.1×10-18 J to ...
Calculation of Frequency of Emitted Photon


Step 1: Calculate Energy Change

The energy change of electron can be calculated by taking the difference between final and initial energy levels. Therefore, the energy change is given as:
-2.4×10-18 J - (-1.1×10-18 J) = -1.3×10-18 J

Step 2: Calculate Frequency of Photon

The frequency of the emitted photon can be calculated using the Planck's equation:
E = hν
where E is the energy change, h is the Planck's constant (6.626×10-34 J.s) and ν is the frequency of photon.

Therefore, the frequency of the emitted photon is given as:
ν = E/h = (-1.3×10-18 J)/(6.626×10-34 J.s) = 1.964×1015 Hz

Step 3: Convert Frequency to Wavelength

The wavelength of the emitted photon can be calculated using the speed of light equation:
c = νλ
where c is the speed of light (3.00×108 m/s) and λ is the wavelength of photon.

Therefore, the wavelength of the emitted photon is given as:
λ = c/ν = (3.00×108 m/s)/(1.964×1015 Hz) = 1.53×10-7 m

Conclusion

The frequency of the emitted photon is 1.964×1015 Hz and its wavelength is 1.53×10-7 m.
Community Answer
An electron in an atom drops from an energy leveal at -1.1×10-18 J to ...
Use the eq ∆E=hc/(lambda).... u will get the value of lambda=154nm
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An electron in an atom drops from an energy leveal at -1.1×10-18 J to an energy level at -2.4×10-18 J. The wave associated with the emitted photon has a frequency?
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