Find the descrimination of3xsqaure-2x 1/3hence find nature if root?
Q. 3x square - 2x + 1/3
solution :- take LCM , so the LCM is 3
(3x square - 2x + 1 )/ 3
so the new quadratic polynomial is :
k(9x square - 6x +1 )
a = 9 , b = -6 , c = 1
so, we have to find discriminant
D = (b) square - 4 (a) (c)
D = (-6) square - 4 (9) (1)
D = 36 - 36
D = 0
discriminant is equal to zero.
so the roots are real and equal.
Find the descrimination of3xsqaure-2x 1/3hence find nature if root?
Discriminant of the quadratic equation
The discriminant of a quadratic equation in the form of ax^2 + bx + c is given by the formula: Δ = b^2 - 4ac. For the equation 3x^2 - 2x + 1/3, a = 3, b = -2, and c = 1/3. Let's calculate the discriminant.
Calculating the discriminant
Δ = (-2)^2 - 4(3)(1/3) = 4 - 4 = 0
The discriminant is zero in this case, which means the roots of the quadratic equation are real and equal.
Nature of the roots
1. When the discriminant is zero, the roots of the quadratic equation are real and equal.
2. In this case, the equation has two identical roots.
3. The equation 3x^2 - 2x + 1/3 has real and equal roots.
Therefore, the nature of the roots of the quadratic equation 3x^2 - 2x + 1/3 is real and equal.