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Find out Ka for 10^-2M HCN acid , having pOH is 10 :- (1)Ka=10^-4 (2)Ka=10^-2 (3)Ka= 10^-5 (4) None?
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Find out Ka for 10^-2M HCN acid , having pOH is 10 :- (1)Ka=10^-4 (2)K...
Solution:
Given, concentration of HCN acid = 10^-2 M
pOH = 10
pH + pOH = 14
Therefore, pH = 4
Now, we can write the balanced chemical equation for the dissociation of HCN as follows:
HCN + H2O ⇌ H3O+ + CN^-
Let the concentration of HCN that dissociates be ‘x’.
Then, the concentration of H3O+ = x
The concentration of CN^- = x
The concentration of remaining HCN = 10^-2 - x
Applying the law of mass action, we get
Ka = [H3O+][CN^-]/[HCN]
Ka = x^2/(10^-2 - x)
Since x < 10^-2,="" we="" can="" assume="" that="" (10^-2="" -="" x)="" ≈="" />
Hence, Ka = x^2/10^-2
Taking the square root on both sides, we get
x/√(10^-2) = Ka^(1/2)
x = Ka^(1/2) x √(10^-2)
Putting the value of x in the expression for Ka, we get
Ka = (Ka^(1/2) x √(10^-2))^2/(10^-2)
Ka = Ka x 10^-2
Ka = 10^-2
Therefore, the correct option is (2)Ka=10^-2.
Explanation:
- Given concentration of HCN acid = 10^-2 M and pOH = 10.
- pH + pOH = 14, therefore pH = 4.
- Balanced chemical equation for the dissociation of HCN is HCN + H2O ⇌ H3O+ + CN^-.
- Let the concentration of HCN that dissociates be ‘x’.
- Then, the concentration of H3O+ = x and the concentration of CN^- = x.
- The concentration of remaining HCN = 10^-2 - x.
- Applying the law of mass action, we get Ka = [H3O+][CN^-]/[HCN].
- Simplifying the expression, we get Ka = x^2/(10^-2 - x).
- Since x < 10^-2,="" we="" can="" assume="" that="" (10^-2="" -="" x)="" ≈="" />
- Hence, Ka = x^2/10^-2.
- Taking the square root on both sides, we get x/√(10^-2) = Ka^(1/2).
- Putting the value of x in the expression for Ka, we get Ka = (Ka^(1/2) x √(10^-2))^2/(10^-2).
- Simplifying the expression, we get Ka = Ka x 10^-2.
- Therefore, Ka = 10^-2.
- Hence, the correct option is (2)Ka=10^-2.
Given, concentration of HCN acid = 10^-2 M
pOH = 10
pH + pOH = 14
Therefore, pH = 4
Now, we can write the balanced chemical equation for the dissociation of HCN as follows:
HCN + H2O ⇌ H3O+ + CN^-
Let the concentration of HCN that dissociates be ‘x’.
Then, the concentration of H3O+ = x
The concentration of CN^- = x
The concentration of remaining HCN = 10^-2 - x
Applying the law of mass action, we get
Ka = [H3O+][CN^-]/[HCN]
Ka = x^2/(10^-2 - x)
Since x < 10^-2,="" we="" can="" assume="" that="" (10^-2="" -="" x)="" ≈="" />
Hence, Ka = x^2/10^-2
Taking the square root on both sides, we get
x/√(10^-2) = Ka^(1/2)
x = Ka^(1/2) x √(10^-2)
Putting the value of x in the expression for Ka, we get
Ka = (Ka^(1/2) x √(10^-2))^2/(10^-2)
Ka = Ka x 10^-2
Ka = 10^-2
Therefore, the correct option is (2)Ka=10^-2.
Explanation:
- Given concentration of HCN acid = 10^-2 M and pOH = 10.
- pH + pOH = 14, therefore pH = 4.
- Balanced chemical equation for the dissociation of HCN is HCN + H2O ⇌ H3O+ + CN^-.
- Let the concentration of HCN that dissociates be ‘x’.
- Then, the concentration of H3O+ = x and the concentration of CN^- = x.
- The concentration of remaining HCN = 10^-2 - x.
- Applying the law of mass action, we get Ka = [H3O+][CN^-]/[HCN].
- Simplifying the expression, we get Ka = x^2/(10^-2 - x).
- Since x < 10^-2,="" we="" can="" assume="" that="" (10^-2="" -="" x)="" ≈="" />
- Hence, Ka = x^2/10^-2.
- Taking the square root on both sides, we get x/√(10^-2) = Ka^(1/2).
- Putting the value of x in the expression for Ka, we get Ka = (Ka^(1/2) x √(10^-2))^2/(10^-2).
- Simplifying the expression, we get Ka = Ka x 10^-2.
- Therefore, Ka = 10^-2.
- Hence, the correct option is (2)Ka=10^-2.
Community Answer
Find out Ka for 10^-2M HCN acid , having pOH is 10 :- (1)Ka=10^-4 (2)K...
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Find out Ka for 10^-2M HCN acid , having pOH is 10 :- (1)Ka=10^-4 (2)Ka=10^-2 (3)Ka= 10^-5 (4) None?
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Find out Ka for 10^-2M HCN acid , having pOH is 10 :- (1)Ka=10^-4 (2)Ka=10^-2 (3)Ka= 10^-5 (4) None? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Find out Ka for 10^-2M HCN acid , having pOH is 10 :- (1)Ka=10^-4 (2)Ka=10^-2 (3)Ka= 10^-5 (4) None? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find out Ka for 10^-2M HCN acid , having pOH is 10 :- (1)Ka=10^-4 (2)Ka=10^-2 (3)Ka= 10^-5 (4) None?.
Find out Ka for 10^-2M HCN acid , having pOH is 10 :- (1)Ka=10^-4 (2)Ka=10^-2 (3)Ka= 10^-5 (4) None? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Find out Ka for 10^-2M HCN acid , having pOH is 10 :- (1)Ka=10^-4 (2)Ka=10^-2 (3)Ka= 10^-5 (4) None? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find out Ka for 10^-2M HCN acid , having pOH is 10 :- (1)Ka=10^-4 (2)Ka=10^-2 (3)Ka= 10^-5 (4) None?.
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