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Calculate the enthalpy of vapourisation of SO2 at-25 degree C if the same at its boiling point be5950 cal/mol.Given the molar heat capacity Cp (l) is 20.6 cal/ Mol and Cp (g) is 9.3 cal/ mol?
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Calculate the enthalpy of vapourisation of SO2 at-25 degree C if the s...
Enthalpy of vapourisation of SO2 at -25 degree C
Given:
Enthalpy of vapourisation of SO2 at its boiling point = 5950 cal/mol
Molar heat capacity of SO2 in liquid state (Cp (l)) = 20.6 cal/mol
Molar heat capacity of SO2 in gaseous state (Cp (g)) = 9.3 cal/mol
To calculate:
Enthalpy of vapourisation of SO2 at -25 degree C
Solution:
Step 1: Calculate the temperature difference between the boiling point of SO2 and -25 degree C
Temperature difference (ΔT) = boiling point of SO2 - (-25 degree C) = (SO2 boils at -10 degree C) - (-25 degree C) = 15 degree C
Step 2: Calculate the enthalpy change required to heat the liquid SO2 from -25 degree C to its boiling point
Enthalpy change (ΔH1) = moles x Cp(l) x ΔT
Moles = 1 (as we are calculating for 1 mole of SO2)
Cp(l) = 20.6 cal/mol
ΔT = 15 degree C = 15 K
ΔH1 = 1 x 20.6 x 15 = 309 cal/mol
Step 3: Calculate the enthalpy change required for the vaporisation of SO2 at its boiling point
Enthalpy change (ΔH2) = 5950 cal/mol
Step 4: Calculate the enthalpy change required to cool down the gaseous SO2 from its boiling point to -25 degree C
Enthalpy change (ΔH3) = moles x Cp(g) x ΔT
Moles = 1 (as we are calculating for 1 mole of SO2)
Cp(g) = 9.3 cal/mol
ΔT = -15 degree C = -15 K
ΔH3 = 1 x 9.3 x (-15) = -139.5 cal/mol
Step 5: Calculate the enthalpy of vapourisation of SO2 at -25 degree C
Enthalpy of vapourisation of SO2 at -25 degree C (ΔH) = ΔH1 + ΔH2 + ΔH3
ΔH = 309 + 5950 - 139.5 = 5969.5 cal/mol
Therefore, the enthalpy of vapourisation of SO2 at -25 degree C is 5969.5 cal/mol.
Explanation:
Enthalpy of vapourisation is the amount of energy required to change 1 mole of a liquid substance to its gaseous state. To calculate the enthalpy of vapourisation of SO2 at -25 degree C, we need to consider the enthalpy changes involved in heating the liquid SO2 to its boiling point, vaporisation of SO2 at its boiling point, and cooling down the gaseous SO2 to -25 degree C.
We use the molar heat capacity of SO2 in liquid and gaseous states to calculate the enthalpy change required to heat and cool down the substance. The enthalpy change required for the vaporisation of SO2 at its boiling point is given in the question
Given:
Enthalpy of vapourisation of SO2 at its boiling point = 5950 cal/mol
Molar heat capacity of SO2 in liquid state (Cp (l)) = 20.6 cal/mol
Molar heat capacity of SO2 in gaseous state (Cp (g)) = 9.3 cal/mol
To calculate:
Enthalpy of vapourisation of SO2 at -25 degree C
Solution:
Step 1: Calculate the temperature difference between the boiling point of SO2 and -25 degree C
Temperature difference (ΔT) = boiling point of SO2 - (-25 degree C) = (SO2 boils at -10 degree C) - (-25 degree C) = 15 degree C
Step 2: Calculate the enthalpy change required to heat the liquid SO2 from -25 degree C to its boiling point
Enthalpy change (ΔH1) = moles x Cp(l) x ΔT
Moles = 1 (as we are calculating for 1 mole of SO2)
Cp(l) = 20.6 cal/mol
ΔT = 15 degree C = 15 K
ΔH1 = 1 x 20.6 x 15 = 309 cal/mol
Step 3: Calculate the enthalpy change required for the vaporisation of SO2 at its boiling point
Enthalpy change (ΔH2) = 5950 cal/mol
Step 4: Calculate the enthalpy change required to cool down the gaseous SO2 from its boiling point to -25 degree C
Enthalpy change (ΔH3) = moles x Cp(g) x ΔT
Moles = 1 (as we are calculating for 1 mole of SO2)
Cp(g) = 9.3 cal/mol
ΔT = -15 degree C = -15 K
ΔH3 = 1 x 9.3 x (-15) = -139.5 cal/mol
Step 5: Calculate the enthalpy of vapourisation of SO2 at -25 degree C
Enthalpy of vapourisation of SO2 at -25 degree C (ΔH) = ΔH1 + ΔH2 + ΔH3
ΔH = 309 + 5950 - 139.5 = 5969.5 cal/mol
Therefore, the enthalpy of vapourisation of SO2 at -25 degree C is 5969.5 cal/mol.
Explanation:
Enthalpy of vapourisation is the amount of energy required to change 1 mole of a liquid substance to its gaseous state. To calculate the enthalpy of vapourisation of SO2 at -25 degree C, we need to consider the enthalpy changes involved in heating the liquid SO2 to its boiling point, vaporisation of SO2 at its boiling point, and cooling down the gaseous SO2 to -25 degree C.
We use the molar heat capacity of SO2 in liquid and gaseous states to calculate the enthalpy change required to heat and cool down the substance. The enthalpy change required for the vaporisation of SO2 at its boiling point is given in the question
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Calculate the enthalpy of vapourisation of SO2 at-25 degree C if the same at its boiling point be5950 cal/mol.Given the molar heat capacity Cp (l) is 20.6 cal/ Mol and Cp (g) is 9.3 cal/ mol?
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Calculate the enthalpy of vapourisation of SO2 at-25 degree C if the same at its boiling point be5950 cal/mol.Given the molar heat capacity Cp (l) is 20.6 cal/ Mol and Cp (g) is 9.3 cal/ mol? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Calculate the enthalpy of vapourisation of SO2 at-25 degree C if the same at its boiling point be5950 cal/mol.Given the molar heat capacity Cp (l) is 20.6 cal/ Mol and Cp (g) is 9.3 cal/ mol? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate the enthalpy of vapourisation of SO2 at-25 degree C if the same at its boiling point be5950 cal/mol.Given the molar heat capacity Cp (l) is 20.6 cal/ Mol and Cp (g) is 9.3 cal/ mol?.
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