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Calculate entropy change for the process H2O(l,293K,1atm) to H2O(g,523K,1atm) ? given cpm of water vapour = 35joule per mole per Kelvin and cpm for water is 75 joule permole per Kelvin and heat of vapourisation(H2O) is equal to 2259.3 joule per gram?
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Calculate entropy change for the process H2O(l,293K,1atm) to H2O(g,523...
Calculating entropy change for the process H2O(l,293K,1atm) to H2O(g,523K,1atm)
Definition of entropy
Entropy is a measure of the disorder or randomness of a system.
Formula for calculating entropy change
ΔS = Sfinal - Sinitial
Calculation of initial entropy
The initial state of the system is H2O(l) at 293K and 1 atm. The entropy of liquid water at this temperature and pressure can be obtained from a table of standard entropy values. The value is 69.91 J/mol K.
Calculation of final entropy
The final state of the system is H2O(g) at 523K and 1 atm. The entropy of water vapor at this temperature and pressure can be obtained from a table of standard entropy values. The value is 188.72 J/mol K.
Calculating entropy change
ΔS = Sfinal - Sinitial = 188.72 - 69.91 = 118.81 J/mol K
Explanation of the result
The positive value of ΔS indicates that the process of water boiling is accompanied by an increase in disorder or randomness of the system. This is because the liquid water molecules are more ordered and closely packed than the water vapor molecules, which are more dispersed and randomly arranged. The increase in temperature and pressure causes the water molecules to gain kinetic energy and break intermolecular bonds, leading to the formation of a less ordered gas phase.
Definition of entropy
Entropy is a measure of the disorder or randomness of a system.
Formula for calculating entropy change
ΔS = Sfinal - Sinitial
Calculation of initial entropy
The initial state of the system is H2O(l) at 293K and 1 atm. The entropy of liquid water at this temperature and pressure can be obtained from a table of standard entropy values. The value is 69.91 J/mol K.
Calculation of final entropy
The final state of the system is H2O(g) at 523K and 1 atm. The entropy of water vapor at this temperature and pressure can be obtained from a table of standard entropy values. The value is 188.72 J/mol K.
Calculating entropy change
ΔS = Sfinal - Sinitial = 188.72 - 69.91 = 118.81 J/mol K
Explanation of the result
The positive value of ΔS indicates that the process of water boiling is accompanied by an increase in disorder or randomness of the system. This is because the liquid water molecules are more ordered and closely packed than the water vapor molecules, which are more dispersed and randomly arranged. The increase in temperature and pressure causes the water molecules to gain kinetic energy and break intermolecular bonds, leading to the formation of a less ordered gas phase.
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Calculate entropy change for the process H2O(l,293K,1atm) to H2O(g,523K,1atm) ? given cpm of water vapour = 35joule per mole per Kelvin and cpm for water is 75 joule permole per Kelvin and heat of vapourisation(H2O) is equal to 2259.3 joule per gram?
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Calculate entropy change for the process H2O(l,293K,1atm) to H2O(g,523K,1atm) ? given cpm of water vapour = 35joule per mole per Kelvin and cpm for water is 75 joule permole per Kelvin and heat of vapourisation(H2O) is equal to 2259.3 joule per gram? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Calculate entropy change for the process H2O(l,293K,1atm) to H2O(g,523K,1atm) ? given cpm of water vapour = 35joule per mole per Kelvin and cpm for water is 75 joule permole per Kelvin and heat of vapourisation(H2O) is equal to 2259.3 joule per gram? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate entropy change for the process H2O(l,293K,1atm) to H2O(g,523K,1atm) ? given cpm of water vapour = 35joule per mole per Kelvin and cpm for water is 75 joule permole per Kelvin and heat of vapourisation(H2O) is equal to 2259.3 joule per gram?.
Calculate entropy change for the process H2O(l,293K,1atm) to H2O(g,523K,1atm) ? given cpm of water vapour = 35joule per mole per Kelvin and cpm for water is 75 joule permole per Kelvin and heat of vapourisation(H2O) is equal to 2259.3 joule per gram? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Calculate entropy change for the process H2O(l,293K,1atm) to H2O(g,523K,1atm) ? given cpm of water vapour = 35joule per mole per Kelvin and cpm for water is 75 joule permole per Kelvin and heat of vapourisation(H2O) is equal to 2259.3 joule per gram? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate entropy change for the process H2O(l,293K,1atm) to H2O(g,523K,1atm) ? given cpm of water vapour = 35joule per mole per Kelvin and cpm for water is 75 joule permole per Kelvin and heat of vapourisation(H2O) is equal to 2259.3 joule per gram?.
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