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Rectangular bar 40mm ×20mm is subjected to steady tensile load of 200Kn find the factor of safety if the yield strength of the material is 500 MPa?
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Rectangular bar 40mm ×20mm is subjected to steady tensile load of 200K...
Rectangular Bar Tensile Load Factor of Safety Calculation


Given


  • Rectangular bar dimensions: 40mm ×20mm

  • Steady tensile load: 200Kn

  • Material yield strength: 500 MPa



Calculations

The cross-sectional area of the rectangular bar is:

Area = length × width = 40mm × 20mm = 800 mm2


The stress on the bar is:

Stress = Load / Area

Stress = 200000 N / 800 mm2 = 250 MPa


The factor of safety is:

Factor of Safety = Yield Strength / Stress

Factor of Safety = 500 MPa / 250 MPa = 2


Interpretation

The factor of safety for the rectangular bar under the given load is 2. This means that the bar can withstand twice the load it is subjected to before it reaches the yield point. Therefore, the design is safe and will not fail under the given load.
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Rectangular bar 40mm ×20mm is subjected to steady tensile load of 200Kn find the factor of safety if the yield strength of the material is 500 MPa?
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